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c如何在结构中创建动态数组指针

[英]c how to make a dynamic array pointer in a struct

I am taking in input from the user for the number of elemenets inside an array. 我正在接受用户输入的数组中元素的数量。 The array is inside my struct 'Polymer' 该数组在我的结构“ Polymer”中

struct Polymer
{
    int length;

    struct Monomer *monomer;

}polymer;

In main, I am creating a new monomer array pointer and setting the mononomer pointer in "Polymer" to it 总的来说,我正在创建一个新的单体数组指针,并将“聚合物”中的单体指针设置为其

struct Monomer *monomers[size];
polymer.monomer = momomers;

I am getting the error "Assignment from incompatible pointer type" which I assume is because we are converting a monomer array pointer to a monomer. 我收到错误“我从不兼容的指针类型分配”,我认为这是因为我们正在将单体数组指针转换为单体。 How do I declare it as a monomer array pointer in the struct? 如何在结构中将其声明为单体数组指针?

You are declaring an array of monomer pointers when you probably want an array of monomers . 当您可能需要一个单体数组时,您将声明一个单体指针 数组 Drop the * : 删除*

struct Monomer monomers[size];
polymer.monomer = momomers;
struct Monomer *monomers[size];
polymer.monomer = momomers;

monomers is an array of pointers . monomers是一个指针数组 They aren't pointing to any valid locations and has garbage values. 它们没有指向任何有效位置,并且具有垃圾值。 While Polymer::monomer is a pointer . Polymer::monomer指针 Array of pointers isn't type compatible to just a pointer. 指针数组不仅仅与指针兼容。

Instead try - 而是尝试-

struct Monomer monomers[size];
polymer.monomer = momomers;  // 2

Now this statement 2 is valid because array decays to a pointer. 现在,该语句2是有效的,因为数组会衰减为指针。

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