[英]c how to make a dynamic array pointer in a struct
I am taking in input from the user for the number of elemenets inside an array. 我正在接受用户输入的数组中元素的数量。 The array is inside my struct 'Polymer'
该数组在我的结构“ Polymer”中
struct Polymer
{
int length;
struct Monomer *monomer;
}polymer;
In main, I am creating a new monomer array pointer and setting the mononomer pointer in "Polymer" to it 总的来说,我正在创建一个新的单体数组指针,并将“聚合物”中的单体指针设置为其
struct Monomer *monomers[size];
polymer.monomer = momomers;
I am getting the error "Assignment from incompatible pointer type" which I assume is because we are converting a monomer array pointer to a monomer. 我收到错误“我从不兼容的指针类型分配”,我认为这是因为我们正在将单体数组指针转换为单体。 How do I declare it as a monomer array pointer in the struct?
如何在结构中将其声明为单体数组指针?
You are declaring an array of monomer pointers when you probably want an array of monomers . 当您可能需要一个单体数组时,您将声明一个单体指针 数组 。 Drop the
*
: 删除
*
:
struct Monomer monomers[size];
polymer.monomer = momomers;
struct Monomer *monomers[size];
polymer.monomer = momomers;
monomers
is an array of pointers . monomers
是一个指针数组 。 They aren't pointing to any valid locations and has garbage values. 它们没有指向任何有效位置,并且具有垃圾值。 While
Polymer::monomer
is a pointer . 而
Polymer::monomer
是指针 。 Array of pointers isn't type compatible to just a pointer. 指针数组不仅仅与指针兼容。
Instead try - 而是尝试-
struct Monomer monomers[size];
polymer.monomer = momomers; // 2
Now this statement 2 is valid because array decays to a pointer. 现在,该语句2是有效的,因为数组会衰减为指针。
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