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将关联记录的顺序保存在Rails has_many中:通过关联

[英]Saving the order of associated records in a Rails has_many :through association

I'm working on a Rails plugin that includes a way to modify the order of associated records in a has_many :through association. 我正在开发一个Rails插件,该插件包括一种修改has_many:through关联中关联记录顺序的方法。 Say we have the following models: 假设我们有以下模型:

class Playlist < ActiveRecord::Base
  has_many :playlists_songs, :dependent => :destroy
  has_many :songs, :through => :playlists_songs
end

class Song < ActiveRecord::Base
  has_many :playlists_songs, :dependent => :destroy
  has_many :playlists, :through => :playlists_songs
end

class PlaylistsSong < ActiveRecord::Base
  belongs_to :playlist
  belongs_to :song
end

If we change the order of a Playlist's Songs (eg @playlist.songs.rotate! ), Rails doesn't touch the records in the playlists_songs table (I'm using Rails 3.1), which makes sense. 如果我们更改播放列表的歌曲的顺序(例如@playlist.songs.rotate! ),Rails不会触摸playlists_songs表中的记录(我使用的是Rails 3.1),这很有意义。 I'd like to make any call to Playlist's songs= method save the order of the Songs, though, perhaps by either deleting the relevant existing rows in playlists_songs and creating new ones in the proper order (so that :order => "id" could be used when retrieving them) or by adding a sort:integer column to playlists_songs and updating those values accordingly. 我想对Playlist的songs =方法进行任何调用,以保存Songs的顺序,也许是通过删除playlists_songs中现有的相关行并以适当的顺序创建新行(以便:order => "id"可以在检索它们时使用)或通过在playlists_songs中添加sort:integer列并相应地更新这些值。

I didn't see any callbacks (eg before_add) that would allow this. 我没有看到任何允许这样做的回调(例如before_add)。 In ActiveRecord::Associations::CollectionAssociation , the relevant methods seem to be writer , replace , and replace_records , but I'm lost on what the best next step would be. ActiveRecord :: Associations :: CollectionAssociation中 ,相关的方法似乎是writerreplacereplace_records ,但是我对下一步的最佳方法迷失了。 Is there a way to extend or safely override one of these methods to allow for the functionality I'm seeking (preferably for only specific associations), or is there a different, better approach for this? 有没有一种方法可以扩展或安全地覆盖这些方法中的一种,以允许我正在寻找的功能(最好仅针对特定的关联),或者是否有其他更好的方法呢?

Have you looked at acts_as_list ? 您看过act_as_list吗? It's one of the most old-school of rails plugins, and is intended to handle this sort of problem. 它是最古老的Rails插件之一,旨在解决此类问题。

Rather than sorting on id , it sorts on a positional column. 而不是对id排序,而是对位置列进行排序。 Then it's simply a matter of updating the position, rather than the messy business of changing the id or deleting/replacing records. 然后,仅需更新位置,而不是更改id或删除/替换记录的麻烦事务。

In your case, you'd simply add a position integer column to PlayListSong , then: 在您的情况下,您只需将position整数列添加到PlayListSong ,然后:

class PlayListSong
  acts_as_list :scope => :play_list_id
end

As you point out in the comments, the methods in acts_as_list work mostly on individual items in the list, and there's no "reorder" functionality out of the box. 正如您在注释中指出的那样, acts_as_list的方法主要对列表中的单个项目起作用,并且没有开箱即用的“重新排序”功能。 I would not recommend tampering with replace_records to do this. 我不建议篡改replace_records来做到这一点。 It would be cleaner and more explicit to write a method making use of the same position column as the plugin. 编写一种使用与插件相同的position列的方法会更加简洁明了。 For example. 例如。

class PlayList
  # It makes sense for these methods to be on the association.  You might make it
  # work for #songs instead (as in your question), but the join table is what's
  # keeping the position.
  has_many :play_list_songs, ... do

    # I'm not sure what rotate! should do, so...

    # This first method makes use of acts_as_list's functionality
    #
    # This should take the last song and move it to the first, incrementing 
    # the position of all other songs, effectively rotating the list forward 
    # by 1 song.
    def rotate!
      last.move_to_top unless empty?
    end

    # this, on the other hand, would reorder given an array of play_list_songs.
    # 
    # Note: this is a rough (untested) idea and could/should be reworked for 
    # efficiency and safety. 
    def reorder!(reordered_songs)
      position = 0
      reordered_songs.each do |song|
        position += 1

        # Note: update_column is 3.1+, but I'm assuming you're using it, since
        # that was the source you linked to in your question
        find(song.id).update_column(:position, position)
      end
    end
  end
end

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