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为什么断言在这里失败

[英]Why does assertion fail here

Why does the assertion fail here when i create a CvMat * ? 为什么创建CvMat *时断言在这里失败? It does not happen with an image i load in cv::Mat using a pointer. 我使用指针在cv :: Mat中加载的图像不会发生这种情况。

    struct RGB { unsigned char b, g, r; };
    cv::Point p;
    RGB *data;
    CvMat* mat = cvCreateMat(300,300,CV_32FC1);
    for( row = 0; row < mat->rows; ++row) 
    {
            for ( col = 0; col < mat->cols; ++col) 
            {
                 p.x=row,p.y=col;
        ERROR ----->>>   assert((mat->step/mat->cols) == sizeof(RGB));
                 data = (RGB*)&mat->data;
                 data += p.y * mat->cols + p.x;
            }
    }

For this code the assertion does not fail: 对于此代码,断言不会失败:

    IplImage * img=cvLoadImage("blah.jpg");
    int row=0,col=0;
    cv::Mat in(img);
    cv::Mat *mat=&in;
    cv::Point p;
    struct RGB { unsigned char b, g, r; };
    RGB *data;
    for( row = 0; row < mat->rows; ++row) 
    {
            for ( col = 0; col < mat->cols; ++col) 
            {
                 p.x=row,p.y=col;
                 assert((mat->step/mat->cols) == sizeof(RGB));
                 data = (RGB*)&mat->data;
                 data += p.y * mat->cols + p.x;
                 printf("Row=%dxCol=%d      b=%u g=%u r=%u\n",row,col,data->b,data->g,data->r);
                 wait_for_frame(1);
            }
    }

Because sizeof(RGB) != sizeof(float) , which is what you filled the matrix with here: 因为sizeof(RGB) != sizeof(float) ,这是您在此处用矩阵填充的内容:

 CvMat* mat = cvCreateMat(300,300,CV_32FC1); 

CV_32FC1 means 1 component, 32-bit floating point. CV_32FC1表示1个组件,32位浮点。 You probably want CV_8UC3 . 您可能需要CV_8UC3 See here or another OpenCV reference. 请参阅此处或其他OpenCV参考。

You can skip the entire IplImage misery if you use cv::Mat img = cv::loadImage("blah.jpg"); 如果使用cv::Mat img = cv::loadImage("blah.jpg");则可以跳过整个IplImage痛苦过程cv::Mat img = cv::loadImage("blah.jpg"); Also it is better to use row ptr for going through all the pixels. 另外,最好使用行ptr遍历所有像素。
It knows the jumps, so you don't have to worry! 它知道跳跃,所以您不必担心!

From the refman: 来自refman:

If you need to process a whole row of a 2D array, the most efficient way is to get the pointer to the row first, and then just use the plain C operator [] 如果您需要处理2D数组的整行,最有效的方法是先获取指向该行的指针,然后再使用普通的C运算符[]

Be aware that if you are loading bigger images which have "jumps" in their data, your code will not work. 请注意,如果要加载较大的图像,这些图像的数据中有“跳转”,则代码将无法工作。 In your situation 在你的情况下

cv::Mat img = cv::loadImage("blah.jpg");
const cv::Mat& M = img;
for(int i = 0; i < rows; i++) 
{
    const Vec3b* Mi = M.ptr<Vec3b>(i); 
    for(int j = 0; j < cols; j++)
    {
        const Vec3b& Mij = Mi[j];
        std::cout<<"Row="<<i<<"Col="<<j<<"\t";
        std::cout<<"b="<<Mij[0]<<" g="<<Mij[1]<<" r="<<Mij[2]<<std::endl;
    }
}

is the fastest correct way. 是最快的正确方法。 Otherwise you could use M.at<Vec3b>(i,j) . 否则,您可以使用M.at<Vec3b>(i,j)

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