变量的C ++ Borland地址

Question

int main(int argc, char* argv[])
{
        int *pInt;
        int iParam = 423425;
        pInt = &iParam;
        std::cout<<&pInt<<std::endl;
        system("pause");
        return 0;
}

Why am i getting address like 1250008 and not like 0x00000 ?

Answer 1

It returns you the addresss where pInt is located in virtual memory.
It can be any address. The compiler is free to place an pointer at any address in the address space allocated to an process.

If you mean to get the address in hex and not decimal, you need to do use I/O Manipulator like this:

std::cout << hex << &pInt << std::endl; 

Answer 2

If you execute the statement printf("%x", iParam), The value stored in iParam is converted into hex and printed but it will not be started with 0X. The same scenario is also in case of printing address. It does not starts with 0X.