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Question

Is there a way to render inside my view of controller A a partial view from other controller B ?

Edit: I wrote a partial view that is good for only two controllers and I don't want to copy it to their both Views folder.
I want The partial view to be displayed each time the View is rendered not after something happens.

Answer 1

1. You can share views between controllers by putting them into the Views/Shared folder. Each controller can then render that view by name.
2. You can render a partial view (which can be shared between controllers as in (1)) within the current view using Html.Partial() .
3. You can use Html.Action() to invoke an action on a different controller and render the results within the current view.
4. You can use AJAX to load a partial view from a different controller after the page has been rendered.

Answer 2

@Html.Partial("~/Views/ControllerB/Index.cshtml")

Answer 3

Yes,

return PartialView("/path/view.cshtml");

You just need to work out the path part.

Alternatively you can put the partial view in views/shared then just return :

return PartialView("view.cshtml");

Answer 4

@model YourModelNamesapce.ModelName
@{
    ViewBag.Title = "Edit";
    Layout = "~/Views/Shared/_LayoutForPartialViews.cshtml";
}
<table>
    <tr>
       <td>
          @Html.LabelFor(model => model.fieldname)
       </td>
       <td>
          @Html.DisplayFor(model => model.fieldname)
       </td>
    </tr>
    <tr>
       <td>@Html.Action("PartialViewAction", "Controller", new { id = Model.id })</td>
    </tr>
</table>

Answer 5

Just a side note as i found this thread searching for the same question but the answers weren't working: in Orchard CMS modules you cannot use the neat solution posted by Pittfall, you have to use relative paths to return partial views. Lets say you have a controller

Controllers/SiteController.cs

and you want to return the partial view

Shared/MessageList/Items

then in your action methods you need to write

return PartialView("../Shared/MessageList/Items");