上传图像以及如何使用GROUP BY和MAX（）在SQL中获取图像

Question

$result = mysql_query("SELECT * FROM photos WHERE accountID = '{$accID}' GROUP BY album_name ORDER BY photo_number DESC");
if(mysql_num_rows($result) != 0) {
    while( $row = mysql_fetch_array($result) ) {
        echo "<div class=\"myPhotos\"><img title='Album: {$row['album_name']}' src=\"images/profile/".$row['photo_link']."\"/></div>";
    }
}else{
    echo "No Album Created";
}

My Intension: is to get the HIGHER 'photo_number' value, while I am also grouping them by their own respective 'album_name' however my $result cant recognize the TOP/HIGHER 'photo_number'(AUTO INCREMENT attribute) how could I recognize the HIGHER 'photo_number' ?

they said that I need to use MAX(photo_number) but, how to code that MAX() syntax?...I hope that you can help me in this problem...

Answer 1

It isn't perfectly clear but I guess you want the highest photo number for each album name and then to sort by that number. If that's the case you'll want something like...

SELECT album_name,
       MAX(photo_number) AS highest_photo_number
    FROM photos
    WHERE accountID = (whatever)
    GROUP BY album_name
    ORDER BY highest_photo_number;