[英]ORACLE Group query by week, month and year
I have a bunch of queries that take data with a time stamp and spit out SUMS based the last few weeks, months, and year to date. 我有一堆查询,这些查询带有时间戳,并根据最近几周,几个月和年初的时间吐出SUMS。 It looks like this
看起来像这样
Week1 Sum for most recent week
Week2 Sum for second most recent week
WeekN Sum for N most recent week
Jan-Dec Sum for January-December
YTD Sum for everything this year
This is how the query currently does this 这是查询当前执行此操作的方式
SELECT TIME_PERIOD, INDEX, SUM(ITEM)
FROM (SELECT
INDEX ,
(CASE
WHEN ACTIVITY_DAY>=(TO_DATE( :end_day,
'yyyy-mm-dd' )-6)
AND ACTIVITY_DAY<=(TO_DATE( :end_day,
'yyyy-mm-dd' )-0) THEN 'WEEK1'
WHEN ACTIVITY_DAY>=(TO_DATE( :end_day,
'yyyy-mm-dd' )-13)
AND ACTIVITY_DAY<=(TO_DATE( :end_day,
'yyyy-mm-dd' )-7) THEN 'WEEK2'
ELSE NULL
END) AS TIME_PERIOD,
MAX(ITEMS) AS ITEM
FROM
SOURCE
GROUP BY
INDEX ,
DAY
UNION
ALL SELECT
INDEX ,
(CASE
WHEN ACTIVITY_DAY>=TO_DATE( :year||'-01-01',
'yyyy-mm-dd' )
AND ACTIVITY_DAY<=TO_DATE( :year||'-01-31',
'yyyy-mm-dd' ) THEN 'Jan'
WHEN ACTIVITY_DAY>=TO_DATE( :year||'-02-01',
'yyyy-mm-dd' )
AND ACTIVITY_DAY<TO_DATE( :year||'-03-01',
'yyyy-mm-dd' ) THEN 'Feb'
ELSE NULL
END) AS TIME_PERIOD ,
MAX(ITEMS) AS ITEM
FROM
SOURCE
GROUP BY
INDEX ,
DAY
UNION
ALL SELECT
INDEX ,
(CASE
WHEN ACTIVITY_DAY>=TO_DATE( :year||'-01-01',
'yyyy-mm-dd' )
AND ACTIVITY_DAY<=TO_DATE( :end_day,
'yyyy-mm-dd' ) THEN 'YTD'
ELSE NULL
END) AS TIME_PERIOD,
MAX(ITEMS) AS ITEM
FROM
SOURCE
GROUP BY
INDEX ,
DAY)
GROUP BY INDEX, TIME_PERIOD
Is there a better way in Oracle? Oracle中有更好的方法吗?
I think you are looking for something like this: 我认为您正在寻找这样的东西:
with data as
(
select sysdate - floor(dbms_random.value(1,400)) dt, floor(dbms_random.value(1,100)) val
from dual
connect by level <= 100
)
select
time_period,
sum(val) period_sum
from
(
select -- weeks
'Week'||(to_char(sysdate, 'WW') - to_char(dt, 'WW') + 1) time_period,
val,
(to_char(sysdate, 'WW') - to_char(dt, 'WW') + 1) ord
from data
where dt >= trunc(sysdate,'YY')
union all
select -- months
to_char(dt, 'Mon') time_period,
val,
100+to_char(dt,'MM') ord
from data
where dt >= trunc(sysdate,'YY')
union all
select -- months
'YTD' time_period,
val,
200
from data
where dt >= trunc(sysdate,'YY')
)
group by
time_period, ord
order by
ord;
Note that you won't need the WITH block, I was just using it to create some dummy data. 请注意,您不需要WITH块,我只是用它来创建一些伪数据。 The Ord column might be unnecessary for you, I was just using it to order the data in a logical fashion.
您可能不需要Ord列,我只是使用它来以逻辑方式对数据进行排序。
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