[英]How to query GROUP BY Month in a Year
I am using Oracle SQL Developer.我正在使用 Oracle SQL Developer。 I essentially have a table of pictures that holds the columns:
我基本上有一个包含列的图片表:
[DATE_CREATED(date), NUM_of_PICTURES(int)] [DATE_CREATED(日期),NUM_of_PICTURES(整数)]
and if I do a select *, I would get an output similar to:如果我选择 *,我会得到类似于以下的输出:
01-May-12 12
02-May-12 15
03-May-12 09
...
...
01-Jun-12 20
...
etc.
I am trying to aggregate these sums of pictures into MONTHLY numbers instead of DAILY.我正在尝试将这些图片总和汇总为每月的数字而不是每天的数字。
I've tried doing something like:我试过做类似的事情:
select Month(DATE_CREATED), sum(Num_of_Pictures))
from pictures_table
group by Month(DATE_CREATED);
This outputs an error:这会输出一个错误:
ORA-00904: "MONTH": invalid identifier
00904. 00000 - "%s: invalid identifier"
*Cause:
*Action:
Error at Line: 5 Column: 9
Do I have the Month function wrong?我的月功能错了吗?
I would be inclined to include the year in the output.我倾向于在输出中包含年份。 One way:
单程:
select to_char(DATE_CREATED, 'YYYY-MM'), sum(Num_of_Pictures)
from pictures_table
group by to_char(DATE_CREATED, 'YYYY-MM')
order by 1
Another way (more standard SQL):另一种方式(更标准的 SQL):
select extract(year from date_created) as yr, extract(month from date_created) as mon,
sum(Num_of_Pictures)
from pictures_table
group by extract(year from date_created), extract(month from date_created)
order by yr, mon;
Remember the order by, since you presumably want these in order, and there is no guarantee about the order that rows are returned in after a group by.请记住 order by,因为您可能希望这些按顺序排列,并且不能保证在 group by 之后返回行的顺序。
For Oracle:对于甲骨文:
select EXTRACT(month from DATE_CREATED), sum(Num_of_Pictures)
from pictures_table
group by EXTRACT(month from DATE_CREATED);
I am doing like this in MSSQL我在 MSSQL 中这样做
Getting Monthly Data:获取每月数据:
SELECT YEAR(DATE_CREATED) [Year], MONTH(DATE_CREATED) [Month],
DATENAME(MONTH,DATE_CREATED) [Month Name], SUM(Num_of_Pictures) [Pictures Count]
FROM pictures_table
GROUP BY YEAR(DATE_CREATED), MONTH(DATE_CREATED),
DATENAME(MONTH, DATE_CREATED)
ORDER BY 1,2
Getting Monthly Data using PIVOT:使用 PIVOT 获取每月数据:
SELECT *
FROM (SELECT YEAR(DATE_CREATED) [Year],
DATENAME(MONTH, DATE_CREATED) [Month],
SUM(Num_of_Pictures) [Pictures Count]
FROM pictures_table
GROUP BY YEAR(DATE_CREATED),
DATENAME(MONTH, DATE_CREATED)) AS MontlySalesData
PIVOT( SUM([Pictures Count])
FOR Month IN ([January],[February],[March],[April],[May],
[June],[July],[August],[September],[October],[November],
[December])) AS MNamePivot
For MS SQL you can do this.对于 MS SQL,您可以这样做。
select CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+
CAST(DATEPART(YEAR, DateTyme) as VARCHAR) as 'Date' from #temp
group by Name, CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+
CAST(DATEPART(YEAR, DateTyme) as VARCHAR)
You can use:您可以使用:
select FK_Items,Sum(PoiQuantity) Quantity from PurchaseOrderItems POI
left join PurchaseOrder PO ON po.ID_PurchaseOrder=poi.FK_PurchaseOrder
group by FK_Items,DATEPART(MONTH, TransDate)
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