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如何查询GROUP BY Month in Year

[英]How to query GROUP BY Month in a Year

I am using Oracle SQL Developer.我正在使用 Oracle SQL Developer。 I essentially have a table of pictures that holds the columns:我基本上有一个包含列的图片表:

[DATE_CREATED(date), NUM_of_PICTURES(int)] [DATE_CREATED(日期),NUM_of_PICTURES(整数)]

and if I do a select *, I would get an output similar to:如果我选择 *,我会得到类似于以下的输出:

01-May-12    12
02-May-12    15
03-May-12    09
...
...
01-Jun-12    20
...
etc.

I am trying to aggregate these sums of pictures into MONTHLY numbers instead of DAILY.我正在尝试将这些图片总和汇总为每月的数字而不是每天的数字。

I've tried doing something like:我试过做类似的事情:

select Month(DATE_CREATED), sum(Num_of_Pictures))
from pictures_table
group by Month(DATE_CREATED);

This outputs an error:这会输出一个错误:

ORA-00904: "MONTH": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:
Error at Line: 5 Column: 9

Do I have the Month function wrong?我的月功能错了吗?

I would be inclined to include the year in the output.我倾向于在输出中包含年份。 One way:单程:

select to_char(DATE_CREATED, 'YYYY-MM'), sum(Num_of_Pictures)
from pictures_table
group by to_char(DATE_CREATED, 'YYYY-MM')
order by 1

Another way (more standard SQL):另一种方式(更标准的 SQL):

select extract(year from date_created) as yr, extract(month from date_created) as mon,
       sum(Num_of_Pictures)
from pictures_table
group by extract(year from date_created), extract(month from date_created)
order by yr, mon;

Remember the order by, since you presumably want these in order, and there is no guarantee about the order that rows are returned in after a group by.请记住 order by,因为您可能希望这些按顺序排列,并且不能保证在 group by 之后返回行的顺序。

For Oracle:对于甲骨文:

select EXTRACT(month from DATE_CREATED), sum(Num_of_Pictures)
from pictures_table
group by EXTRACT(month from DATE_CREATED);

I am doing like this in MSSQL我在 MSSQL 中这样做

Getting Monthly Data:获取每月数据:

 SELECT YEAR(DATE_CREATED) [Year], MONTH(DATE_CREATED) [Month], 
     DATENAME(MONTH,DATE_CREATED) [Month Name], SUM(Num_of_Pictures) [Pictures Count]
    FROM pictures_table
    GROUP BY YEAR(DATE_CREATED), MONTH(DATE_CREATED), 
     DATENAME(MONTH, DATE_CREATED)
    ORDER BY 1,2

Getting Monthly Data using PIVOT:使用 PIVOT 获取每月数据:

SELECT *
FROM (SELECT YEAR(DATE_CREATED) [Year], 
       DATENAME(MONTH, DATE_CREATED) [Month], 
       SUM(Num_of_Pictures) [Pictures Count]
      FROM pictures_table
      GROUP BY YEAR(DATE_CREATED), 
      DATENAME(MONTH, DATE_CREATED)) AS MontlySalesData
PIVOT( SUM([Pictures Count])   
    FOR Month IN ([January],[February],[March],[April],[May],
    [June],[July],[August],[September],[October],[November],
    [December])) AS MNamePivot

For MS SQL you can do this.对于 MS SQL,您可以这样做。

    select  CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+ 
CAST(DATEPART(YEAR, DateTyme) as VARCHAR) as 'Date' from #temp
    group by Name, CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+
 CAST(DATEPART(YEAR, DateTyme) as VARCHAR) 

You can use:您可以使用:

    select FK_Items,Sum(PoiQuantity) Quantity  from PurchaseOrderItems POI
    left join PurchaseOrder PO ON po.ID_PurchaseOrder=poi.FK_PurchaseOrder
    group by FK_Items,DATEPART(MONTH, TransDate)

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