C ++ Stl Map迭代器输出十六进制值

Question

I have the following code:

map<StatTypesEnum, ValueHandler*>::const_iterator itr;

for(itr=player1->Stats.begin(); itr!=player1->Stats.end(); itr++)
{
    cout << "Stat: " << itr->first << " Value: " << (ValueHandler*)(itr->second)->getValue() << endl;
}

The getValue() method returns an int. If I cout the value outside of the iterator, it displays in base10 decimal, however when i return the value using an iterator (as above) it displays in base16, hex.

Just for completeness, the following line displays as base10:

cout << player1->Stats[Power]->getValue() << endl;

I would like the iterator to display base10.

Thanks.

Answer 1

When you print (ValueHandler*)(itr->second)->getValue() you should be getting a hexadecimal value because that's how pointers are printed. You probably shouldn't be casting the return value of getValue() to a ValueHandler* . You probably intended to cast itr->second to that pointer type (although it's not necessary) but just got the parentheses wrong. Here's what casting itr->second would look like:

((ValueHandler*) itr->second)->getValue()

And what you want is probably:

itr->second->getValue()

Answer 2

(ValueHandler*)(itr->second)->getValue() is a pointer, not an int . You're casting the return value of getValue .

Maybe you want ((ValueHandler*)(itr->second))->getValue() ? Which is redundant anyway.