C ++ STL向量迭代器不兼容

Question

// Erase the missing items
vector<AlignedFDRData>::size_type StandardNum = FDRFreq.at(0).fData.size();
vector<AlignedFDRData>::iterator iter = FDRFreq.begin(); 
while (iter != FDRFreq.end()){
    if( iter->fData.size() < StandardNum){
        FDRFreq.erase(iter);
    }
    else{
        ++iter;
    }
}

This part is used to erase the FDRFreq vector item, in which the data length is smaller than the standard number, but the debug assertion failed: vector iterators incompatible. I am a green hand in C++ STL, thanks for your kindly help.

Answer 1

Your problem is iterator invalidation after the call to std::erase . The warning is triggered by an iterator debugging extensions in your standard library implementation. erase returns an iterator to the new valid location after the erase element and you continue iterating from there. However, this is still very inefficient.

Use the Erase-Remove Idiom to remove data with a predicate from a vector .

FDRFreq.erase(std::remove_if(
                begin(FDRFreq), end(FDRFreq), 
                [&StandardNum](const AlignedFDRData& x) { 
                  return fData.size() > StandardNum; }),
              end(FDRFreq));

Answer 2

Your code needs to become

while (iter != FDRFreq.end()){
    if( iter->fData.size() < StandardNum){
        iter = FDRFreq.erase(iter);
    }
    else{
        ++iter;
    }
}

"vector iterators incompatible" means that the iterator you're using has been invalidated - that is to say, there is no guarantee that the elements it points to still exist at that memory location. An erase of a vector element invalidates the iterators following that location. .erase returns a new, valid iterator you can use instead.

If you're new to STL, I highly recommend you read Scott Myer's Effective STL (and Effective C++ , while you're at it)