尝试从MySQL查询的两个表中获取信息

Question

My page info and images are stored in two separate tables. I want 'type' and 'body' from the table "page". Then 'images' from the table "page_images". Both obviously from the same page.

I want a few teasers of random pages. But, I need ONE image (even though many are stored for each page) from "page_images" and the 'type' and 'body' from "page". (images are stored as 'image_loc' in the table page_images)

-- TABLE  page

page_id | user_id | url_title     | title         | type | full_location | phone | body
----------------------------------------------------------------------------------------
1       | 1       | jazz_showcase | Jazz Showcase | Jazz | ...           | ...   | ... 

-- TABLE  page_images

image_id | user_id | page_title     | image_loc
-----------------------------------------------
1        | 1       | jazz_showcase  | ...
2        | 3       | jazz_showcase  | ...
3        | 2       | something_else | ...

This query doesn't work...

function OnTheSpot() {
        $query = mysql_query("SELECT page.body AS desc, page.style AS styles, page_images.image_loc AS images
                                FROM page
                                LEFT JOIN page_images
                                ON page.url_title = page_images.page_title 
                                ORDER BY RAND()
                                LIMIT 1
                            ");
        while($fetch = mysql_fetch_assoc($query)) {
            $desc = $fetch['desc'];
            $styles = $fetch['styles'];
            $images = $fetch['images'];
            echo $desc.'<br />';
            echo $styles.'<br />';
            echo $images.'<br />';
            }
        }

I would want 5 or so random pages demoed. Each page with a limit of one image and the type and body displayed. How would this be query'd.

Answer 1

Change the desc to eg descr . Desc is a reserved word in MySQL and you can't use it.

See: MySQL Reserved Words

EDIT: Here is also a query for you, which probably solves your problem:

$query = "SELECT page.body AS descr, page.url_title, page.style AS styles, page_images.image_loc AS images FROM page,page_images WHERE page_images.page_title = page.url_title ORDER BY RAND() LIMIT 1");