分别从两个单独的MySQL表中删除信息？

Question

I'm making this podcast-sharing like site where users can upload audio pod-casts and if they log into the admin page can edit each title and each URL, and delete any podcast. Here's my code, I will explain my error afterwards:

    <li><form action="admin.php" method="POST"><input type="submit" name="1" value = "Insects and Plants" /><input type="submit" name="2" value = "Dr. Seuss" /></forM>
    <li><p><?php
    function disp($titid,$titol,$aid){

            if($_GET['del']){
            $delete_id=$_GET['del'];
            mysql_query("DELETE FROM `$titid` WHERE `$titid`.`inid` = $delete_id");
            header("location: admin.php");

            }
    echo "<a name='$aid'><h3>" . $titol . "</h3></a>";
    $result=mysql_query('SELECT * FROM `'.$titid.'` ORDER BY inid ASC');
            while($row=mysql_fetch_array($result))
            {
            $title = $row['title'];

            $url=$row['url'];
            $id = $row['inid'];
            echo '<div class="inneredit">';
            echo $title . '</br>';
            echo $url . '</br>'.$id.'</br>';

                    echo "<form action='admin.php' method='POST'><input type='text' name='nameedit".$id."' /><input type='submit' name='nameit$id' value='Edit Name' /></form>";
            echo "<form action='admin.php' method='POST'><input type='text' name='urledit".$id."' /><input type='submit' name='redit$id' value='Edit URL' /></form>";
            echo "<input type='button' id='delete' value='Delete Podcast' onclick='return Deleteqry($id)' />";
            echo "</div>";
            if(isset($_POST['urledit'.$id]));
                    if(isset($_POST['redit'.$id]))
                    {
                        $newd = $_POST['urledit'.$id];

                        mysql_query("UPDATE `$titid` SET url = '$newd' WHERE $titid.inid = $id ");
                        header("location: admin.php");
                    }
                                    if(isset($_POST['nameit'.$id]))
                    {
                        $newd = $_POST['nameedit'.$id];

                        mysql_query("UPDATE `$titid` SET title = '$newd' WHERE $titid.inid = $id ");
                        header("location: admin.php");
                    }
            }

            }
            if(isset($_POST['2'])){
            disp("DrSeuss","Dr. Seuss","Seussa");

            } else {
            disp("insects","Insects and Plants","Insectsa");
    }
            ?>
    <script>
            function Deleteqry(id)
            { 
              if(confirm("Are you sure you want to delete this audio file?")==true)
                       window.location="admin.php?del="+id;
                return false;
            }

    </script>



            ?>

So now when I click delete after selecting 'Dr. Seuss' it deletes the podcast (with that same id) but in the Insects table, and not the Dr. Seuss table. Can anyone help with how to help PHP differentiate between the two tables?

Answer 1

看一下您的js函数，便会发现您没有设置$ _POST ['2']，因此不会执行DrSeuss上的if条件。