Linux命令为目录中的所有文件提供文件扩展名

Question

I came up with this:

for i in *; 
do input=`echo $i|sed -e 's/[ ]/\\\ /g'`; 
output=`echo $input".mp3"`; 
mv $input $output; done

Its very close, but it mv complains:

mv: invalid option -- '\\'

I don't quite get why it won't work if I try echoing $input or $output they both seem to properly escape all the spaces in the file names and nothing more.

Answer 1

find . -type f -exec mv "{}" "{}.mp3" \\;

Answer 2

It looks like you are massively over-complicating this with your use of sed (and echo )...

You are trying to escape space characters in file names, but you really just need to enclose the filename in quotation marks. You can simply do...

for i in *; do
    mv "${i}" "${i}.mp3"
done

Answer 3

Shorter and safer :

for i; do
    mv -- "${i}" "${i}.mp3"
done

=)

-- takes care of files starting with a dash

and for i in * is shortened by for i

Use more quotes : they are vital. Also, learn the difference between ' , " and ` . See http://mywiki.wooledge.org/Quotes and http://wiki.bash-hackers.org/syntax/words . ( sentence stolen from IRC freenode #bash )

Answer 4

使用重命名 ，它使这些事情变得非常简单：

rename 's/$/.mp3/' *

Answer 5

for i in *; do mv -- ${i}{,.mp3};done