Linux命令在目录中查找具有相同名称但扩展名不同的所有文件？

Question

I am working on a project where i need to deal with lots of files with the same name but different extensions.

please suggest a command/solution to get the file name.

Thanks in advance

Answer 1

您的助手是find命令

find /<directory_name> -name  <file_name.\*>

Answer 2

find "$searchdir" -name "${filespec%.*}".\*

will find all files in $searchdir named "foo" with a file extension if $filespec is of the form "foo.bar".

Of course, if $filespec is of the form "foo.bar.baz", you will find all files named "foo.bar" with a file extension, so beware of such files.

If you want only the root filename (eg "foo.bar.baz.quux" -> "foo"), then you should use %% instead of % after the filespec variable.

If you need to strip a preceding directory name from the filespec, you could combine this with the basename utility:

find "$searchdir" -name "$(basename "${filespec%.*}")".\*