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正则表达式匹配任何字符,包括新行

[英]Regex to match any character including new lines

Is there a regex to match "all characters including newlines"?是否有正则表达式匹配“包括换行符在内的所有字符”?

For example, in the regex below, there is no output from $2 because (.+?) doesn't include new lines when matching.例如,在下面的正则表达式中, $2没有输出,因为(.+?)在匹配时不包含新行。

$string = "START Curabitur mollis, dolor ut rutrum consequat, arcu nisl ultrices diam, adipiscing aliquam ipsum metus id velit. Aenean vestibulum gravida felis, quis bibendum nisl euismod ut. 

Nunc at orci sed quam pharetra congue. Nulla a justo vitae diam eleifend dictum. Maecenas egestas ipsum elementum dui sollicitudin tempus. Donec bibendum cursus nisi, vitae convallis ante ornare a. Curabitur libero lorem, semper sit amet cursus at, cursus id purus. Cras varius metus eu diam vulputate vel elementum mauris tempor. 

Morbi tristique interdum libero, eu pulvinar elit fringilla vel. Curabitur fringilla bibendum urna, ullamcorper placerat quam fermentum id. Nunc aliquam, nunc sit amet bibendum lacinia, magna massa auctor enim, nec dictum sapien eros in arcu. 

Pellentesque viverra ullamcorper lectus, a facilisis ipsum tempus et. Nulla mi enim, interdum at imperdiet eget, bibendum nec END";

$string =~ /(START)(.+?)(END)/;

print $2;

If you don't want add the /s regex modifier (perhaps you still want . to retain its original meaning elsewhere in the regex), you may also use a character class.如果您不想添加/s正则表达式修饰符(也许您仍然希望.在正则表达式的其他地方保留其原始含义),您也可以使用字符类。 One possibility:一种可能:

[\S\s]

a character which is not a space or is a space.不是空格或空格的字符。 In other words, any character.换句话说,任何字符。

You can also change modifiers locally in a small part of the regex, like so:您还可以在正则表达式的一小部分本地更改修饰符,如下所示:

(?s:.)

Add the s modifier to your regex to cause .s修饰符添加到您的正则表达式以导致. to match newlines:匹配换行符:

$string =~ /(START)(.+?)(END)/s;

Yeap, you just need to make .是的,你只需要 make . match newline :匹配换行符:

$string =~ /(START)(.+?)(END)/s;

您想使用“多行”。

$string =~ /(START)(.+?)(END)/m;

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