正则表达式：匹配除逗号以外的任何字符（包括空格）

Question

I would like to match any character and any whitespace except comma with regex. Only matching any character except comma gives me:

[^,]*

but I also want to match any whitespace characters, tabs, space, newline, etc. anywhere in the string.

EDIT:

This is using sed in vim via :%s/foo/bar/gc.

I want to find starting from func up until the comma, in the following example:

func("bla bla bla"
  "asdfasdfasdfasdfasdfasdf"
"asdfasdfasdf", "more strings")

I

Answer 1

To work with multiline in SED using RegEx , you should look at here .

EDIT:

In SED command, working with NewLine is a bit different. SED command support three patterns to manage multiline operations N , P and D . To see how it works see this (Working with Multiple Lines) explaination. Here these three operations discussed.

My guess is that N operator is the area of consideration that is missing from here. Addition of N operator will allows to sense \\n in string.

An example from here :

Occasionally one wishes to use a new line character in a sed script. Well, this has some subtle issues here. If one wants to search for a new line, one has to use "\\n." Here is an example where you search for a phrase, and delete the new line character after that phrase - joining two lines together.

(echo a;echo x;echo y) | sed '/x$/ { N s:x\\n:x: }'

which generates

a xy

However, if you are inserting a new line, don't use "\\n" - instead insert a literal new line character:

(echo a;echo x;echo y) | sed 's:x:X\\ :'

generates

a X

y

Answer 2

So basically you're trying to match a pattern over multiple lines.

Here's one way to do it in sed (pretty sure these are not useable within vim though, and I don't know how to replicate this within vim )

sed '
    /func/{
            :loop
            /,/! {N; b loop}
            s/[^,]*/func("ok"/
    }
' inputfile

Let's say inputfile contains these lines

func("bla bla bla"
  "asdfasdfasdfasdfasdfasdf"
"asdfasdfasdf", "more strings")

The output is

func("ok", "more strings")

---

Details :

• If a line contains func , enter the braces.
• :loop is a label named loop
• If the line does not contain , (that's what /,/! means)
  • append the next line to pattern space ( N )
  • branch to / go to loop label ( b loop )
• So it will keep on appending lines and looping until , is found, upon which the s command is run which matches all characters before the first comma against the (multi-line) pattern space, and performs a replacement.