使用正则表达式匹配除=以外的任何字符

Question

I am trying to write a String validation to match any character (regular, digit and special) except =.

Here is what I have written -

    String patternString = "[[^=][\\w\\s\\W]]*";
    Pattern p = Pattern.compile(patternString);
    Matcher m = p.matcher(str);

    if(m.matches())
        System.out.println("matches");
    else
        System.out.println("does not");

But, it matches the input string "2009-09/09 12:23:12.5=" with the pattern.

How can I exclude = (or any other character, for that matter) from the pattern string?

Answer 1

If the only prohibited character is the equals sign, something like [^=]* should work.

[^...] is a negated character class; it matches a single character which is any character except one from the list between the square brackets. * repeats the expression zero or more times.

Answer 2

First of all, you don't need a regexp. Simply call contains :

if(str.contains("="))
    System.out.println("does not");
else
    System.out.println("matches");

The correct regexp you're looking for is just

String patternString = "[^=]*";

Answer 3

如果您只想检查是否出现“=”，为什么不使用String indexOf（）方法？

if str.indexOf('=')  //...

Answer 4

如果您的目标是在字符串中没有任何=字符，请尝试以下操作

String patternString = "[^=]*";