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我可以覆盖 c# 中的属性吗? 如何?

[英]Can I override a property in c#? How?

I have this Base class:我有这个基类:

abstract class Base
{
  public int x
  {
    get { throw new NotImplementedException(); }
  }
}

And the following descendant:以及以下后代:

class Derived : Base
{
  public int x
  {
    get { //Actual Implementaion }
  }
}

When I compile I get this warning saying Derived class's definition of x is gonna hide Base's version of it.当我编译时,我收到这个警告说派生类的x定义将隐藏它的 Base 版本。 Is is possible to override properties in c# like methods?是否可以像方法一样覆盖 c# 中的属性?

You need to use virtual keyword您需要使用virtual关键字

abstract class Base
{
  // use virtual keyword
  public virtual int x
  {
    get { throw new NotImplementedException(); }
  }
}

or define an abstract property:或定义一个抽象属性:

abstract class Base
{
  // use abstract keyword
  public abstract int x { get; }
}

and use override keyword when in the child:并在孩子中使用override关键字:

abstract class Derived : Base
{
  // use override keyword
  public override int x { get { ... } }
}

If you're NOT going to override, you can use new keyword on the method to hide the parent's definition.如果您不打算覆盖,则可以在方法上使用new关键字来隐藏父级的定义。

abstract class Derived : Base
{
  // use new keyword
  public new int x { get { ... } }
}

Make the base property abstract and override or use the new keyword in the derived class.使基本属性抽象并覆盖或在派生类中使用 new 关键字。

abstract class Base
{
  public abstract int x { get; }
}

class Derived : Base
{
  public override int x
  {
    get { //Actual Implementaion }
  }
}

Or或者

abstract class Base
{
  public int x { get; }
}

class Derived : Base
{
  public new int x
  {
    get { //Actual Implementaion }
  }
}

Change property signature as shown below:更改属性签名如下所示:

Base class基类

public virtual int x 
{ get { /* throw here*/ } }

Derived class派生类

public override int x 
{ get { /*overriden logic*/ } }

If you do not need any implementation in Base class just use abstract property.如果您不需要基类中的任何实现,只需使用抽象属性。

Base:根据:

public abstract int x { get; }

Derived:衍生的:

public override int x { ... }

I would suggest you using abstract property rather than trhowing NotImplemented exception in getter, abstact modifier will force all derived classes to implement this property so you'll end up with compile-time safe solution.我建议您使用abstract属性而不是在 getter 中抛出 NotImplemented 异常, abstact修饰符将强制所有派生类实现此属性,因此您最终会得到编译时安全的解决方案。

abstract class Base
{

  public virtual int x
  {
    get { throw new NotImplementedException(); }
  }
}

or或者

abstract class Base
{
  // use abstract keyword
  public abstract int x
  {
    get;
  }
}

In both case you have to write in the derived class在这两种情况下,您都必须在派生类中编写

public override int x
  {
    get { your code here... }
  }

difference between the two is that with abstract you force the derived class to implement something, and with virtaul you can provide a default behavior that the deriver can use as is, or change.两者之间的区别在于,使用 abstract 可以强制派生类实现某些东西,而使用 virtaul 可以提供派生者可以按原样使用或更改的默认行为。

abstract class Base 
{ 
  // use abstract keyword 
  public virtual int x 
  { 
    get { throw new NotImplementedException(); } 
  } 
} 

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