如何使用单个foreach迭代两个相同长度的集合

Question

I know this question has been asked many times before but I tried out the answers and they don't seem to work.

I have two lists of the same length but not the same type, and I want to iterate through both of them at the same time as list1[i] is connected to list2[i] .

Eg:

Assuming that i have list1 (as List<string> ) and list2 (as List<int> )

I want to do something like

foreach( var listitem1, listitem2 in list1, list2)
{
   // do stuff
}

Is this possible?

Answer 1

This is possible using .NET 4 LINQ Zip() operator or using open source MoreLINQ library which provides Zip() operator as well so you can use it in more earlier .NET versions

Example from MSDN :

int[] numbers = { 1, 2, 3, 4 };
string[] words = { "one", "two", "three" };

// The following example concatenates corresponding elements of the
// two input sequences.
var numbersAndWords = numbers.Zip(words, (first, second) => first + " " + second);
foreach (var item in numbersAndWords)
{
    Console.WriteLine(item);
}

// OUTPUT:
// 1 one
// 2 two
// 3 three

Useful links:

• Soure code of the MoreLINQ Zip() implementation: MoreLINQ Zip.cs

Answer 2

Edit - Iterating whilst positioning at the same index in both collections

If the requirement is to move through both collections in a 'synchronized' fashion, ie to use the 1st element of the first collection with the 1st element of the second collection, then 2nd with 2nd, and so on, without needing to perform any side effecting code, then see @sll's answer and use .Zip() to project out pairs of elements at the same index, until one of the collections runs out of elements.

More Generally

Instead of the foreach , you can access the IEnumerator from the IEnumerable of both collections using the GetEnumerator() method and then call MoveNext() on the collection when you need to move on to the next element in that collection. This technique is common when processing two or more ordered streams, without needing to materialize the streams.

var stream1Enumerator = stream1.GetEnumerator();
var stream2Enumerator = stream2.GetEnumerator();
var currentGroupId = -1; // Initial value
// i.e. Until stream1Enumerator runs out of 
while (stream1Enumerator.MoveNext())
{
   // Now you can iterate the collections independently
   if (stream1Enumerator.Current.Id != currentGroupId)
   {
       stream2Enumerator.MoveNext();
       currentGroupId = stream2Enumerator.Current.Id;
   }
   // Do something with stream1Enumerator.Current and stream2Enumerator.Current
}

As others have pointed out, if the collections are materialized and support indexing, such as an ICollection interface, you can also use the subscript [] operator, although this feels rather clumsy nowadays:

var smallestUpperBound = Math.Min(collection1.Count, collection2.Count);
for (var index = 0; index < smallestUpperBound; index++)
{
     // Do something with collection1[index] and collection2[index]
}

Finally, there is also an overload of Linq's .Select() which provides the index ordinal of the element returned, which could also be useful.

eg the below will pair up all elements of collection1 alternatively with the first two elements of collection2 :

var alternatePairs = collection1.Select(
    (item1, index1) => new 
    {
        Item1 = item1,
        Item2 = collection2[index1 % 2]
    });

Answer 3

Short answer is no you can't.

Longer answer is that is because foreach is syntactic sugar - it gets an iterator from the collection and calls Next on it. This is not possible with two collections at the same time.

If you just want to have a single loop, you can use a for loop and use the same index value for both collections.

for(int i = 0; i < collectionsLength; i++)
{
   list1[i];
   list2[i];
}

An alternative is to merge both collections into one using the LINQ Zip operator (new to .NET 4.0) and iterate over the result.

Answer 4

foreach(var tup in list1.Zip(list2, (i1, i2) => Tuple.Create(i1, i2)))
{
  var listItem1 = tup.Item1;
  var listItem2 = tup.Item2;
  /* The "do stuff" from your question goes here */
}

It can though be such that much of your "do stuff" can go in the lambda that here creates a tuple, which would be even better.

If the collections are such that they can be iterated, then a for() loop is probably simpler still though.

Update: Now with the built-in support for ValueTuple in C#7.0 we can use:

foreach ((var listitem1, var listitem2) in list1.Zip(list2, (i1, i2) => (i1, i2)))
{
    /* The "do stuff" from your question goes here */
}

Answer 5

You can wrap the two IEnumerable<> in helper class:

var nums = new []{1, 2, 3};
var strings = new []{"a", "b", "c"};

ForEach(nums, strings).Do((n, s) =>
{
  Console.WriteLine(n + " " + s);
});

//-----------------------------

public static TwoForEach<A, B> ForEach<A, B>(IEnumerable<A> a, IEnumerable<B> b)
{
  return new TwoForEach<A, B>(a, b);   
}

public class TwoForEach<A, B>
{
  private IEnumerator<A> a;
  private IEnumerator<B> b;

  public TwoForEach(IEnumerable<A> a, IEnumerable<B> b)
  {
    this.a = a.GetEnumerator();
    this.b = b.GetEnumerator();
  }

  public void Do(Action<A, B> action)
  {
    while (a.MoveNext() && b.MoveNext())
    {
      action.Invoke(a.Current, b.Current);
    }
  }
}

Answer 6

Instead of a foreach, why not use a for()? for example...

int length = list1.length;
for(int i = 0; i < length; i++)
{
    // do stuff with list1[i] and list2[i] here.
}