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从String中删除重音符号

[英]Remove accents from String

Is there any way in Android that (to my knowledge) doesn't have java.text.Normalizer, to remove any accent from a String. 在Android中是否有任何方法(据我所知)没有java.text.Normalizer,从String中删除任何重音。 Eg "éàù" becomes "eau". 例如“éàù”变成“eau”。

I'd like to avoid parsing the String to check each character if possible! 如果可能的话,我想避免解析String来检查每个字符!

java.text.Normalizer is there in Android (on latest versions anyway). java.text.Normalizer存在于Android中(无论如何最新版本)。 You can use it. 你可以使用它。

EDIT For reference, here is how to use Normalizer : 编辑供参考,以下是使用Normalizer

string = Normalizer.normalize(string, Normalizer.Form.NFD);
string = string.replaceAll("[^\\p{ASCII}]", "");

(pasted from the link in comments below) (粘贴在下面评论中的链接)

I've ajusted Rabi's solution to my needs, I hope it helps someone: 我已经调整了Rabi对我的需求的解决方案,我希望它可以帮助某人:

private static Map<Character, Character> MAP_NORM;
public static String removeAccents(String value)
{
    if (MAP_NORM == null || MAP_NORM.size() == 0)
    {
        MAP_NORM = new HashMap<Character, Character>();
        MAP_NORM.put('À', 'A');
        MAP_NORM.put('Á', 'A');
        MAP_NORM.put('Â', 'A');
        MAP_NORM.put('Ã', 'A');
        MAP_NORM.put('Ä', 'A');
        MAP_NORM.put('È', 'E');
        MAP_NORM.put('É', 'E');
        MAP_NORM.put('Ê', 'E');
        MAP_NORM.put('Ë', 'E');
        MAP_NORM.put('Í', 'I');
        MAP_NORM.put('Ì', 'I');
        MAP_NORM.put('Î', 'I');
        MAP_NORM.put('Ï', 'I');
        MAP_NORM.put('Ù', 'U');
        MAP_NORM.put('Ú', 'U');
        MAP_NORM.put('Û', 'U');
        MAP_NORM.put('Ü', 'U');
        MAP_NORM.put('Ò', 'O');
        MAP_NORM.put('Ó', 'O');
        MAP_NORM.put('Ô', 'O');
        MAP_NORM.put('Õ', 'O');
        MAP_NORM.put('Ö', 'O');
        MAP_NORM.put('Ñ', 'N');
        MAP_NORM.put('Ç', 'C');
        MAP_NORM.put('ª', 'A');
        MAP_NORM.put('º', 'O');
        MAP_NORM.put('§', 'S');
        MAP_NORM.put('³', '3');
        MAP_NORM.put('²', '2');
        MAP_NORM.put('¹', '1');
        MAP_NORM.put('à', 'a');
        MAP_NORM.put('á', 'a');
        MAP_NORM.put('â', 'a');
        MAP_NORM.put('ã', 'a');
        MAP_NORM.put('ä', 'a');
        MAP_NORM.put('è', 'e');
        MAP_NORM.put('é', 'e');
        MAP_NORM.put('ê', 'e');
        MAP_NORM.put('ë', 'e');
        MAP_NORM.put('í', 'i');
        MAP_NORM.put('ì', 'i');
        MAP_NORM.put('î', 'i');
        MAP_NORM.put('ï', 'i');
        MAP_NORM.put('ù', 'u');
        MAP_NORM.put('ú', 'u');
        MAP_NORM.put('û', 'u');
        MAP_NORM.put('ü', 'u');
        MAP_NORM.put('ò', 'o');
        MAP_NORM.put('ó', 'o');
        MAP_NORM.put('ô', 'o');
        MAP_NORM.put('õ', 'o');
        MAP_NORM.put('ö', 'o');
        MAP_NORM.put('ñ', 'n');
        MAP_NORM.put('ç', 'c');
    }

    if (value == null) {
        return "";
    }

    StringBuilder sb = new StringBuilder(value);

    for(int i = 0; i < value.length(); i++) {
        Character c = MAP_NORM.get(sb.charAt(i));
        if(c != null) {
            sb.setCharAt(i, c.charValue());
        }
    }

    return sb.toString();

}

This is probably not the most efficient solution but it will do the trick and it works in all Android versions: 这可能不是最有效的解决方案,但它可以解决问题,它适用于所有Android版本:

private static Map<Character, Character> MAP_NORM;
static { // Greek characters normalization
    MAP_NORM = new HashMap<Character, Character>();
    MAP_NORM.put('ά', 'α');
    MAP_NORM.put('έ', 'ε');
    MAP_NORM.put('ί', 'ι');
    MAP_NORM.put('ό', 'ο');
    MAP_NORM.put('ύ', 'υ');
    MAP_NORM.put('ή', 'η');
    MAP_NORM.put('ς', 'σ');
    MAP_NORM.put('ώ', 'ω');
    MAP_NORM.put('Ά', 'α');
    MAP_NORM.put('Έ', 'ε');
    MAP_NORM.put('Ί', 'ι');
    MAP_NORM.put('Ό', 'ο');
    MAP_NORM.put('Ύ', 'υ');
    MAP_NORM.put('Ή', 'η');
    MAP_NORM.put('Ώ', 'ω');
}

public static String removeAccents(String s) {
    if (s == null) {
        return null;
    }
    StringBuilder sb = new StringBuilder(s);

    for(int i = 0; i < s.length(); i++) {
        Character c = MAP_NORM.get(sb.charAt(i));
        if(c != null) {
            sb.setCharAt(i, c.charValue());
        }
    }

    return sb.toString();
}

While Guillaume's answer does work it strips all non-ASCII characters from the string. 虽然Guillaume的答案确实有效,但它会从字符串中删除所有非ASCII字符。 If you wish to preserve these try this code (where string is the string to simplify): 如果你想保留这些,请尝试这段代码(其中string是要简化的字符串):

// Convert input string to decomposed Unicode (NFD) so that the
// diacritical marks used in many European scripts (such as the
// "C WITH CIRCUMFLEX" → ĉ) become separate characters.
// Also use compatibility decomposition (K) so that characters,
// that have the exact same meaning as one or more other
// characters (such as "㎏" → "kg" or "ヒ" → "ヒ"), match when
// comparing them.
string = Normalizer.normalize(string, Normalizer.Form.NFKD);

StringBuilder result = new StringBuilder();

int offset = 0, strLen = string.length();
while(offset < strLen) {
    int character = string.codePointAt(offset);
    offset += Character.charCount(character);

    // Only process characters that are not combining Unicode
    // characters. This way all the decomposed diacritical marks
    // (and some other not-that-important modifiers), that were
    // part of the original string or produced by the NFKD
    // normalizer above, disappear.
    switch(Character.getType(character)) {
        case Character.NON_SPACING_MARK:
        case Character.COMBINING_SPACING_MARK:
            // Some combining character found
        break;

        default:
            result.appendCodePoint(Character.toLowerCase(character));
    }
}

// Since we stripped all combining Unicode characters in the
// previous while-loop there should be no combining character
// remaining in the string and the composed and decomposed
// versions of the string should be equivalent. This also means
// we do not need to convert the string back to composed Unicode
// before returning it.
return result.toString();

All accented chartacters are in the extended ASCII character code set, with decimal values greater than 127. So you could enumerate all the characters in a string and if the decimal character code value is greater than 127, map it back to your desired equivalent. 所有带重音的图表都在扩展的ASCII字符代码集中,十进制值大于127.因此,您可以枚举字符串中的所有字符,如果十进制字符代码值大于127,则将其映射回所需的等效值。 There is no easy way to map accented characters back to the non-accented counterparts - you would have to keep some sort of map in memory to map the extended decimal codes back to the unaccented characters. 没有简单的方法将重音字符映射回非重音符号 - 您必须在内存中保留某种映射,以将扩展的十进制代码映射回非重音字符。

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