我有一个逗号分隔的字符串，我想在C＃中使用Regex查找一个特定的字段

Question

This is my string:

"0949418001","12/12/2011","12/21/2011","0010043309","EFT  ","Net 10 Days From Ship Date","","","FOB Origin/Collect","","","0000835369","DUPRE TRANSPORTS INC","DUPR      ","0231653047","1/23/2012","Motor Fuel Dest","1049930","8784.00","8796.00","8784.00","UG6  ","N","0.196500","1726.06","25405.51","TAX ","REG","","PASADENA,TX,COP,RFYC (03FV)","   ","0000835369","835369","1726.06","01/23/2012","0.00","23679.45"

I want to get the date that is preceding the word "Motot Fuel Dest" using regex. How can we get that?

Answer 1

Could use something like this...

/(?<=")[^"]+(?=","Motor Fuel Dest)/

Depending on your regex flavor the syntax may be different.

Edit: .NET version of solution

resultString = Regex.Match(subjectString, "(?<=\")[^\"]+(?=\",\"Motor Fuel Dest)").Value;

It's not something special, just lookbehind/lookahead capture only what you need.

Answer 2

This will also work...

var dateMatch = Regex.Match(myInputString, @"(?<Date>\d{1,2}/\d{1,2}/\d{4})"",Motor\sFuel\sDest");

DateTime theValue = DateTime.Parse(dateMatch.Groups["Date"].Value);

Then you have the value as a DateTime in the theValue field.