我有一个逗号分隔的字符串，我想在C＃中使用Regex查找一个特定的字段

Question

这是我的字符串：

"0949418001","12/12/2011","12/21/2011","0010043309","EFT  ","Net 10 Days From Ship Date","","","FOB Origin/Collect","","","0000835369","DUPRE TRANSPORTS INC","DUPR      ","0231653047","1/23/2012","Motor Fuel Dest","1049930","8784.00","8796.00","8784.00","UG6  ","N","0.196500","1726.06","25405.51","TAX ","REG","","PASADENA,TX,COP,RFYC (03FV)","   ","0000835369","835369","1726.06","01/23/2012","0.00","23679.45"

我想使用正则表达式获取"Motot Fuel Dest"一词之前的日期。 我们怎么能得到呢？

Answer 1

可以使用这样的东西...

/(?<=")[^"]+(?=","Motor Fuel Dest)/

根据您的正则表达式风格，语法可能有所不同。

编辑：.NET版本的解决方案

resultString = Regex.Match(subjectString, "(?<=\")[^\"]+(?=\",\"Motor Fuel Dest)").Value;

这没什么特别的，只是先行查找/先行捕获仅需要的内容。

Answer 2

这也将起作用...

var dateMatch = Regex.Match(myInputString, @"(?<Date>\d{1,2}/\d{1,2}/\d{4})"",Motor\sFuel\sDest");

DateTime theValue = DateTime.Parse(dateMatch.Groups["Date"].Value);

然后，在theValue字段中将值作为DateTime 。