不能在PHP中的另一个命名空间内使用Namespaced类

Question

I am still having trouble with PHP5 Namespaces.

I have a namespace called Project and I am trying to access a class called registry inside of this Project namespace that has a namespace of Library so at the top of the file that is a Project namespace I use this line use Library\\Registry;

Registry class is inside the Library Namespace

This should work but it doesn't, instead the ONLY way to access my registry class inside this Project namespace is to use this

$this->registry = new \Library\Registry;

I want to be able to use this instead...

$this->registry = new Registry;

That was the whole reason of using

use Library\Registry;

at the top of the Project namespace file

---

Below I have 3 small example scripts in a folder structure like this.
Library/registry.class.php a class in my Library folder
Controller/controller.class.php and class in my Controller directory
Controller/testing.php a test file to run the script.

E:\\Library\\Registry.class.php file

<?php
namespace Library
{
    class Registry
    {
        function __construct()
        {
            echo 'Registry.class.php Constructor was ran';
        }
    }
}
?>

E:\\Controller\\Controller.class.php file

<?php
use Library\Registry;

namespace Project
{
    class Controller
    {
        public $registry;

        function __construct()
        {
            include('E:\Library\Registry.class.php');

            // This is where my trouble is
            // to make it work currently I have to use
            //  $this->registry = new /Library/Registry;
            // But I want to be able to use it like below and that is why
            // I have the `use Library\Registry;` at the top
            $this->registry = new Registry;
        }

        function show()
        {
            $this->registry;
            echo '<br>Registry was ran inside testcontroller.php<br>';
        }
    }
}
?>

E:\\Controller\\testing.php file

<?php
use Project\Controller;

include('testcontroller.php');

$controller = new Controller();
$controller->show();

?>

I get this error...

Fatal error: Class 'Project\Registry' not found in PATH to file

unless I use this below on the controller.class.php file

$this->registry = new \MyLibrary\Registry;

Because in that file at the top I have use Library\\Registry; I should be able to access it like this...

$this->registry = new Registry;

Please help me get it where I can use it like that instead

Answer 1

use Library\Registry;

namespace Project
{

I believe that's the wrong way round: you're use ing Library\\Registry in the global namespace, and then opening the Project namespace.

Put the use statement inside the namespace you want to import it into.

namespace Project
{
    use Library\Registry;

Answer 2

You need to import your Registry class inside Project namespace, because you need em there, not in global scope.

<?php   
namespace Project
{
    use Library\Registry;

    class Controller
    {
        public $registry;

        function __construct()
        {
            include('E:\Library\Registry.class.php');

            // This is where my trouble is
            // to make it work currently I have to use
            //  $this->registry = new /Library/Registry;
            // But I want to be able to use it like below and that is why
            // I have the `use Library\Registry;` at the top
            $this->registry = new Registry;
        }

        function show()
        {
            $this->registry;
            echo '<br>Registry was ran inside testcontroller.php<br>';
        }
    }
}
?>

Answer 3

Just add: use \\Library\\Registry;

at top of your script under the namespace declaration

Then you can just say:

$registry = new Registry;

inside your class

By the way your class declaration is all wrong. You should not wrap your namespace inside curly braces, namespace is not a function.

This is how it should be. Also make sure the class declaration of Library\\Registry is already included by either using include('/path/to/registry.php'); or using autoloader

namespace Project;

include('E:\\Library\\Registry.class.php');

use \Library\Registry;

    class Controller
    {
        public $registry;

        function __construct()
        {


            // This is where my trouble is
            // to make it work currently I have to use
            //  $this->registry = new /Library/Registry;
            // But I want to be able to use it like below and that is why
            // I have the `use Library\Registry;` at the top
            $this->registry = new Registry;
        }

        function show()
        {
            $this->registry;
            echo '<br>Registry was ran inside testcontroller.php<br>';
        }
    }

Enjoy

Answer 4

<?php namespace Project;
    require_once 'your registry class file';
    use \Library\Registry as Registry;

Now you will be able to use...

    $this->registry = new Registry;