[英]How to pick a random element in a 2 dimensional array
Ok I want to pick a random point in the 2d array so it can be filled. 好的,我想在2d数组中选择一个随机点,以便可以填充它。 Ive seen how to do this for a 1d array, and am wondering how this would be possible in a 2d array.
我已经看过如何对一维数组执行此操作,并且想知道在二维数组中如何做到这一点。 All I have seen about this method is that the same position comes up again, which is a slight problem, but I don't know how to do it in the first place.
我所看到的关于该方法的所有信息是再次出现相同的位置,这是一个小问题,但是我不知道该如何做。 The 2d array is essentially a grid, with the dimensions being the x and y coordinates.
2d数组本质上是一个网格,尺寸为x和y坐标。 And the random element selecting a point within the boundaries (which is user selected but for the purposes of this problem can be 30x50.
并且在边界内选择一个点的随机元素(用户选择该点,但出于此问题的目的,可以为30x50。
EDIT: 编辑:
import java.util.Random;
class pickRand{
public static String get (int x, int y){
int rndx = generator.nextInt(x) + 2;
int rndy = generator.nextInt(y) + 2;
}
}
So would this work, the x and y will correspond to the user generated number and have a raised boundary of 2 either side to prevent any objects going (partially outside or of the grid. Nothing needs to be returned right? 因此,这项工作将使x和y对应于用户生成的数字,并且在任一侧具有2的凸起边界以防止任何对象进入(部分在网格外部或网格之外。不需要返回任何内容吗?
If you grid is of size M by N
如果网格的大小为
M by N
0 and M-1
say i 0 and M-1
之间的随机数,说我 0 and N-1
say j 0 and N-1
之间的随机数,说j (i,j) will be a random element of the 2d array (i,j)将是2d数组的随机元素
What role does the array play here? 数组在这里扮演什么角色?
Essentially, the task is to pick... random integer 2D coordinates . 本质上,任务是选择... 随机整数2D坐标 。
So if you want two coordinates, say i
in 0...W-1
and j
in 0...H-1
, just draw two random integers. 所以,如果你想两个坐标,说
i
在0...W-1
和j
在0...H-1
只画两个随机整数。 If you need more for higher dimensionality, draw more randoms. 如果您需要更高的尺寸,请绘制更多随机数。
Obviously, you can then access array[i][j]
. 显然,您可以访问
array[i][j]
。
In most languages, arrays can however be ragged, ie the rows/columns may have different lengths. 但是,在大多数语言中,数组可能参差不齐,即行/列的长度可能不同。 This is however just as trivial to handle...
但是,这同样不容易处理...
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