[英]Prevent a method from being called if it is incorrect using __getattr__
I am trying to prevent an instance from throwing an exception if a method that does not exist for the instance is called. 我试图阻止实例在调用实例不存在的方法时抛出异常。 I have tried the following:
我尝试过以下方法:
class myClass(object):
def __init__(self):
pass
def __getattr__(self,name):
print "Warning - method {0} does not exist for this instance".format(name)
o = myClass()
var = o.someNonExistantFunction()
The problem is that I get the following error: 问题是我收到以下错误:
TypeError: 'NoneType' object is not callable
The two things I want to make sure of doing is: 我想确保做的两件事是:
None
as my code can deal with variables being set to None
None
因为我的代码可以处理设置为None
变量 What is the cleanest way to do this? 最干净的方法是什么?
return a function that does nothing? 返回一个什么都不做的函数?
Couple of things: first you might want to use __getattr__
rather than __getattribute__
. 几件事:首先你可能想要使用
__getattr__
而不是__getattribute__
。
__getattr__
gets called when the runtime doesn't find anything by that name in the hierarchy, __getattribute__
gets called every time. __getattr__
被调用时,运行时不会在层次结构中找到这个名字什么, __getattribute__
被称为每次。
class Test(object):
def __getattr__(self,key):
def placeholder(*args, **kwargs):
print "Warning - method '%s' does not exist for this instance"%key
return placeholder
Your __getattr__
is the same as: 你的
__getattr__
与以下内容相同:
def __getattr__(self, name):
print "Warning ..."
return None
So, when you do var = o.someNonExistantFunction()
, this is logically the same as: 因此,当你执行
var = o.someNonExistantFunction()
,这在逻辑上与以下相同:
var = o.someNonExistantFunction # == o.__getattr__('someNonExistantFunction') == None
var() # same as (None)()
Which is why you're getting the NoneType not callable error. 这就是为什么你得到NoneType不可调用的错误。 Obtuse definitely has the rest of the answer, which is to return a callable function.
Obtuse肯定有其余的答案,即返回一个可调用的函数。 However, you might think about other structural issues, and if it's truly a good idea to have a catchall function generator.
但是,您可能会考虑其他结构问题,如果拥有一个catchall函数生成器真的是个好主意。
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