[英]How to run a command in bash script which is not stopped when the script exits?
I have a BASH script which runs other commands and I would like to keep them running in case the main script stops. 我有一个BASH脚本运行其他命令,我想让它们运行,以防主脚本停止。 I tried to run those commands with &
but it didn't help. 我尝试用&
运行这些命令,但它没有帮助。 Am I doing something wrong? 难道我做错了什么?
This is normal: the shell's job control mechanism terminates its jobs when it exits. 这是正常的:shell的作业控制机制在退出时终止其作业。
There are at least two solutions: 至少有两种解决方案:
disown
after you have launched a job; 在你找到工作后使用disown
; at
to schedule your job at a later time; 用于at
以后安排你的工作; nohup
command. 或使用nohup
命令。 Now, there is the question of what you want to do with the output of the command you launch in the background: 现在,问题是您要对在后台启动的命令的输出做什么:
disown
, you lose it; 如果被disown
,你就会失去它; at
, stdout and stderr are sent to you by mail (but then you can redirect stdout/stderr if you want); at
,stdout和stderr通过邮件发送给你(但是如果你愿意,你可以重定向stdout / stderr); nohup
, you define the output file yourself. 使用nohup
,您自己定义输出文件。 尝试'nohup'命令运行COMMAND ,忽略挂断信号
nohup COMMAND &
Try using nohup (stands for no hangup) before your command: 在命令之前尝试使用nohup(代表没有挂起):
nohup <your command>
It will forward the stdout of the command into a file called nohup.out by default. 默认情况下,它会将命令的stdout转发到名为nohup.out的文件中。
以下是如何执行此操作的示例:
nohup your_command < /dev/null > output.log 2>&1 &
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