如何删除字符串的第一个和最后一个字符？

Question

I have worked in SOAP message to get LoginToken from Webservice, and store the LoginToken in String and used System.out.println(LoginToken); to print. This prints [wdsd34svdf], but I want only wdsd34svdf so, how to remove square bracket. please any one help me.

Thanks

Example:

String LoginToken=getName().toString();
System.out.println("LoginToken" + LoginToken);

Output: [wdsd34svdf] I want wdsd34svdf

Answer 1

It's easy, You need to find index of [ and ] then substring. (Here [ is always at start and ] is at end) ,

String loginToken = "[wdsd34svdf]";
System.out.println( loginToken.substring( 1, loginToken.length() - 1 ) );

Answer 2

这是通用解决方案：

str.replaceAll("^.|.$", "")

Answer 3

You can always use substring :

String loginToken = getName().toString();
loginToken = loginToken.substring(1, loginToken.length() - 1);

Answer 4

Another solution for this issue is use commons-lang (since version 2.0) StringUtils.substringBetween(String str, String open, String close) method. Main advantage is that it's null safe operation.

StringUtils.substringBetween("[wdsd34svdf]", "[", "]"); // returns wdsd34svdf

Answer 5

I had a similar scenario, and I thought that something like

str.replaceAll("\[|\]", "");

looked cleaner. Of course, if your token might have brackets in it, that wouldn't work.

Answer 6

This way you can remove 1 leading "[" and 1 trailing "]" character. If your string happen to not start with "[" or end with "]" it won't remove anything:

str.replaceAll("^\\[|\\]$", "")

Answer 7

this is perfectly working fine

String str = "[wdsd34svdf]";
//String str1 = str.replace("[","").replace("]", "");
String str1 = str.replaceAll("[^a-zA-Z0-9]", "");
System.out.println(str1);


String strr = "[wdsd(340) svdf]";
String strr1 = str.replaceAll("[^a-zA-Z0-9]", "");
System.out.println(strr1);

Answer 8

In Kotlin

private fun removeLastChar(str: String?): String? {
    return if (str == null || str.isEmpty()) str else str.substring(0, str.length - 1)
}

Answer 9

Try this to remove the first and last bracket of string ex.[1,2,3]

String s =str.replaceAll("[", "").replaceAll("]", "");

Exptected result = 1,2,3

Answer 10

StringUtils 's removeStart and removeEnd method help to remove string from start and end of a string.

In this case we could also use combination of this two method

String string = "[wdsd34svdf]";
System.out.println(StringUtils.removeStart(StringUtils.removeEnd(string, "]"), "["));

Answer 11

SOLUTION 1

def spaceMeOut(str1):

 print(str1[1:len(str1)-1])

str1='Hello'

print(spaceMeOut(str1))

SOLUTION 2

def spaceMeOut(str1):

 res=str1[1:len(str1)-1] print('{}'.format(res))

str1='Hello'

print(spaceMeOut(str1))

Answer 12

This will gives you basic idea

    String str="";
    String str1="";
    Scanner S=new Scanner(System.in);
    System.out.println("Enter the string");
    str=S.nextLine();
    int length=str.length();
    for(int i=0;i<length;i++)
    {
        str1=str.substring(1, length-1);
    }
    System.out.println(str1);