从Zend中的表中选择完全匹配的列...？

Question

I am facing a strange issue in my Zend Application:

My model is like this:

 public function checkEmailAndProfileName($emailId, $proName) {
    $select = $this->select()
                     ->where('email_address = ?', $emailId)
                     ->where('profile_name = ?', $proName);
    $result = $this->getAdapter()->fetchRow($select);
 }

Explanation

Suppose I have a row in database with email address "test@test.com" and profile name as "profilename".

Now if I pass following parameters to the model:

$modelObj->checkEmailAndProfileName("test@test.com", "profilename");

It is working fine as I want.

Problem

Now If I pass:

$modelObj->checkEmailAndProfileName("test@test.com", "ProfileNAME");

Then it should return false, but strangely it is returning the row of "test@test.com", "profilename". That I don't want...

can anyone help me by telling What I am doing wrong...?

Thanks In Advance...

Answer 1

What you need is BINARY of mysql

Using BINARY in the WHERE clause forces a match on the binary collation, which in English means that it matches actual characters by their character code, not by whether the characters are deemed equivalent.

public function checkEmailAndProfileName($emailId, $proName) {
    $select = $this->select()
                     ->where('email_address = ?', $emailId)
                     ->where('BINARY profile_name = ?', $proName);
    $result = $this->getAdapter()->fetchRow($select);
 }