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C:我如何模拟8086寄存器?

[英]C: How do I simulate 8086 registers?

Ohai, I'm currently trying to implement an 8086 ASM debugger for learning purposes. Ohai,我目前正在尝试实现8086 ASM调试器以用于学习目的。 Until now, I tried to simulate the 8 and 16 bit registers with char arrays but this approach is driving me nuts, when working with AX, AL and AH. 到目前为止,我试图用char数组模拟8位和16位寄存器,但这种方法让我疯狂,在使用AX,AL和AH时。

#define setAL() { int i; for (i = 0; i < 8; i++) AL[i] = AX[i]; }
char AX[16]   = {0, 1, 1, 1, 1 ,1 ,1, 0, 0, 0, 0, 0, 0, 0, 0, 0};
char AL[8]    = {0, 0, 0, 0, 0, 0, 0, 0};

Does anyone has any good idea (or something like 'best practice') how to simulate those registers? 有没有人有任何好主意(或类似'最佳实践')如何模拟这些寄存器?

I don't think there's a 'best practice' way of doing this, but one approach you could take that may drive you nuts less is to use a union to overlay the 8 and 16 bit portions: 我不认为有这样做的“最佳实践”方法,但你可以采取的一种方法可能会让你更少疯狂,就是使用一个联合覆盖8位和16位部分:

struct RegByte { 
   unsigned char low;
   unsigned char high;
};

struct RegWord {
   unsigned short value;
};

union Reg {
   struct RegWord word;
   struct RegByte bytes;
};

Alternatively given you're explicitly targeting just 8086 you could have one structure containing all the 16 bit registers and one containing all of the byte portions. 或者,如果你明确地只针对8086,你可以有一个包含所有16位寄存器的结构,一个包含所有字节部分的结构。 eg 例如

struct RegByte {
   unsigned char al, ah, bl, bh, cl, ch, dl, dh;
};

struct RegWord {
   unsigned short ax, bx, cx, dx;
   /* nothing stopping you from continuing with si, di, etc even though
    * they don't have addressable high and low bytes */
};

union Reg {
   struct RegWord word;
   struct RegByte byte;
};

I'd abstract the structure away and use accessor functions. 我将结构抽象出来并使用访问器函数。

struct registry_file_t;
uint16_t get_al(registry_file_t * r);
void set_al(registry_file_t * r, uint16_t value);

With inlining enabled, this approach will be no less performant than using a union. 启用内联后,这种方法的性能不会低于使用联合。

In case it might be useful for someone, I put the one I wrote here. 如果它可能对某人有用,我把我在这里写的那个。

typedef struct cpu_8086_s cpu_t;

struct cpu_8086_s
{
    struct
    {
        union
        {
            uint16_t ax;
            struct
            {
                uint8_t al;
                uint8_t ah;
            };
        };
        union
        {
            uint16_t cx;
            struct
            {
                uint8_t cl;
                uint8_t ch;
            };
        };
        union
        {
            uint16_t dx;
            struct
            {
                uint8_t dl;
                uint8_t dh;
            };
        };
        union
        {
            uint16_t bx;
            struct
            {
                uint8_t bl;
                uint8_t bh;
            };
        };
        uint16_t sp;
        uint16_t bp;
        uint16_t si;
        uint16_t di;
    };
    struct
    {
        uint16_t es;
        uint16_t cs;
        uint16_t ss;
        uint16_t ds;
    };
    uint16_t ip;
    union
    {
        uint16_t flags;
        struct
        {
            uint8_t c: 1;
            uint8_t  : 1;
            uint8_t p: 1;
            uint8_t  : 1;
            uint8_t a: 1;
            uint8_t  : 1;
            uint8_t z: 1;
            uint8_t s: 1;
            uint8_t t: 1;
            uint8_t i: 1;
            uint8_t d: 1;
            uint8_t o: 1;
        };
    };
};

Why not use structure and union like this: 为什么不像这样使用structureunion

union AX_R {
    AX_R() {
        AX = 0;
    }
    unsigned __int16 AX;
    struct {
        unsigned __int8 AL;
        unsigned __int8 AH;
    } _AX_R;
};

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