将值数组放入CLLocationCoordinate2D的绝佳方法

Question

Is there an elegant way to create a CLLocationCoordinate2D object from an array of NSDecimalNumber values? Perhaps a recursive function?

I'm new to objective C and am having difficulty with this.

Below is an example of the data structures I'm working with.

---

an array of NSDecimalNumber values:

NSLog(@"path: %@", [path description]);

returns

path: (
    "-71.4826609644423",
    "27.7231737704478",
    "-71.4826608497223",
    "27.7231120144099",
    "-71.4826391681679",
    "27.7228678610506",
    ...
    "-71.482414263977",
    "27.7225217655116",
)

---

I can manually create the CLLocationCoordinate2D object like this:

CLLocationCoordinate2D pathCoords[5]={
    CLLocationCoordinate2DMake(27.7231737704478,-71.4826609644423),
    CLLocationCoordinate2DMake(27.7231120144099,-71.4826608497223),
    CLLocationCoordinate2DMake(27.7228678610506,-71.4826391681679),
    ...
    CLLocationCoordinate2DMake(27.7225217655116,-71.482414263977),
};

Any coding suggestions are welcome. Thanks!

Answer 1

I'm assuming you have already created a CLLocationCoordinate2D structure called pathCoords of size 5.

for(int i=0;i<[path count]/2;i++)
   pathCoords[i] = CLLocationCoordinate2DMake([path objectAtIndex:2*i+1], [path objectAtIndex:2*i]);

The nature of your problem is not recursive, so if you go recursive - it's an overkill.

Answer 2

The final solution including typecasting the NSDecimalNumbers to doubleValues:

for(int i=0; i<[path count]/2; i++) {
        pathCoords[i] = CLLocationCoordinate2DMake([[path objectAtIndex:2*i+1] doubleValue], [[path objectAtIndex:2*i] doubleValue]);