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C ++类成员函数和来自C API的回调

[英]C++ class member function and callback from C API

I am trying to learn how to call this write_data(…) function from the funmain() function in the class as shown in the code bellow. 我正在尝试学习如何从类中的funmain()函数调用此write_data(…)函数,如下面的代码所示。 (I know this program works if I just list these two functions without putting it inside a class). (我知道如果我只列出这两个函数而不将它放在一个类中,这个程序就可以工作)。

curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data) line gives me error and wouldn't let me call the write_data(…) function. curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data)行给出了错误,不允许我调用write_data(...)函数。 Can you please correct my code and tell me how I can achieve this. 你可以请更正我的代码并告诉我如何实现这一目标。 Any help would be greatly appreciated. 任何帮助将不胜感激。 Thanks. 谢谢。

error C3867: 'go_website::write_data': function call missing argument list; use '&go_website::write_data' to create a pointer to member

//Microsoft Visual Studio 10 in C++
#define CURL_STATICLIB
#include <stdio.h>
#include <curl/curl.h>
#include <curl/types.h>
#include <iostream>
#include <curl/easy.h>
#include <string>
using namespace std;

extern "C" typedef size_t curl_write_callback(void *ptr, size_t size, size_t nmemb, FILE *stream);
class go_website
{
public:
static curl_write_callback write_data;

void funmain()
{
    CURL *curl;
    FILE *fp;
    CURLcode res;
    char *url = "http://www.shorturl.com/";
    char outfilename[FILENAME_MAX] = "C:\\bbb.txt";
    curl = curl_easy_init();
    if (curl) {
        fp = fopen(outfilename,"wb");
        curl_easy_setopt(curl, CURLOPT_URL, url);
        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, &write_data); 
        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, fp);
        res = curl_easy_perform(curl);
        curl_easy_cleanup(curl);
        fclose(fp);
    }
}};

extern "C" size_t write_data(void *ptr, size_t size, size_t nmemb, FILE *stream) 
{
size_t written;
written = fwrite(ptr, size, nmemb, stream);
return written;
}

int main()
{
   go_website a;
   a.funmain();
   return 0;
}

It is possible http://curl.haxx.se/docs/faq.html#Using_C_non_static_functions_f 有可能http://curl.haxx.se/docs/faq.html#Using_C_non_static_functions_f

 // f is the pointer to your object.
 static YourClass::func(void *buffer, size_t sz, size_t n, void *f)
 {
   // Call non-static member function.
   static_cast<YourClass*>(f)->nonStaticFunction();
 }
 // This is how you pass pointer to the static function:
 curl_easy_setopt(hcurl, CURLOPT_WRITEFUNCTION, YourClass:func);
 curl_easy_setopt(hcurl, CURLOPT_WRITEDATA, this);

These two lines won't work: 这两行不起作用:

curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, fp);

The second is the easiest to fix: fp is a file pointer, not a function, you're setting the wrong attribute, I guess you want CURLOPT_WRITEDATA . 第二个是最容易修复的: fp是一个文件指针,而不是一个函数,你设置了错误的属性,我想你想要CURLOPT_WRITEDATA

For the callback function, you need a function pointer. 对于回调函数,您需要一个函数指针。 The name of an ordinary function automatically decays to its address, although using the address-of operator ( &functionname ) is cleaner. 普通函数的名称会自动衰减到其地址,尽管使用address-of运算符( &functionname )更清晰。

Class member functions do not automatically decay. 类成员函数不会自动衰减。 In fact, a non-static class member function is totally incompatible with a normal function pointer, since there's no way to handle this . 实际上,非静态类成员函数与普通函数指针完全不兼容,因为没有办法处理this Luckily you don't need a non-static member function, since no non-static members are used inside the callback. 幸运的是,您不需要非静态成员函数,因为在回调中不使用非静态成员。

Make the callback function static and extern "C" : 使回调函数为 static extern "C"

 
 
 
 
  
  
  extern "C" typedef size_t curl_write_callback(void *ptr, size_t size, size_t nmemb, FILE *stream); class go_website { public: static curl_write_callback write_data; // ... }; extern "C" size_t go_website::write_data(void *ptr, size_t size, size_t nmemb, FILE *stream) { size_t written; written = fwrite(ptr, size, nmemb, stream); return written; }
 
 
  

and then take its address, using the address-of operator and fully-qualified function name: 然后使用address-of运算符和完全限定的函数名取其地址:

 
 
 
 
  
  
  curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, &go_website::write_data);
 
 
  

This part was even explained in the error message. 甚至在错误消息中解释了这部分。 But it didn't tell you that you needed static or extern "C" , this is the problem with variable argument lists, they aren't typesafe. 但它并没有告诉你你需要 staticextern "C" ,这是变量参数列表的问题,它们不是类型安全的。

After reading the Standard (section 7.5 [dcl.link] , and especially paragraph 4 and its examples), this isn't allowed. 在阅读标准(第7.5节[dcl.link] ,特别是第4段及其示例)之后,这是不允许的。 The member function still has C++ language linkage, for both its name (not important) and its type (this is the deal-breaker). 成员函数仍然具有C ++语言链接,因为它的名称(不重要)和它的类型(这是交易破坏者)。

You have to use a global function for the callback: 您必须使用全局函数进行回调:

curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, &write_data);

and then pass a pointer to it: 然后传递一个指向它的指针:

 curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, &write_data); 

I know this program works if I just list these two functions without putting it inside a class 我知道这个程序是有效的,如果我只列出这两个函数而不将它放在一个类中

If it works outside of a class, but not inside, then you likely need to use the "this" pointer. 如果它在类之外工作,但不在内部,那么你可能需要使用“this”指针。

        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, this->write_data);

The problem is that you want the WRITEFUNCTION to be a member function of your class. 问题是你希望WRITEFUNCTION成为你班级的成员函数。 However, curl doesn't know which instance of the class to call it on. 但是,curl不知道要调用它的类的哪个实例。 You need to create a static function that you pass to WRITEFUNCTION and then pass your this pointer as the CURLOPT_WRITEDATA parameter. 您需要创建一个传递给WRITEFUNCTION的静态函数,然后将此指针作为CURLOPT_WRITEDATA参数传递。 Then in your static member function you can use the user_data pointer (which is your "this" from WRITE_DATA) as the instance of the class. 然后在静态成员函数中,您可以使用user_data指针(来自WRITE_DATA的“this”)作为类的实例。

Maybe this question will help: curl WRITEFUNCTION and classes 也许这个问题会有所帮助: curl WRITEFUNCTION和类

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