无法读取C中的EOF字符

Question

I have a problem with reading the EOF character for the last input in C

j=0;       
while(*(name2+j)!='\n'){
    if(*(name2+j) == ' '){
        j++;
        continue;
    }
    d[tolower(*(name2+j))]++;
    j++;
}

For the last input, there is no new line character, the value of j is getting set to very large number for a very small string. So, to consider the end of file, i modified the while condition to

while(*(name2+j)!='\n' && (*(name2+j))!=EOF)

but still i am having the same problem. Can someone tell if i am missing something here ? Thanks.

Answer 1

EOF是超出char范围的整数值（因为它的主要目的是指示不存在 char ），因此，如果您希望能够将值与EOF进行比较，则需要检索该值并将其存储为一个int而不是一个char 。

Answer 2

How did you declare name2 and set it? char can't contain an EOF , but if you got it by the standard input functions, you should have a '\\0' terminates it. if so, just change the condition to

while (name2[j] && name2[j]!='\n')