[英]Find distance of route from get.shortest.paths()
I'm using the igraph
package in R to do something rather simple: Calculate the shortest distance between two nodes in my network. 我在R中使用
igraph
包来做一些相当简单的事情:计算网络中两个节点之间的最短距离。 Is there a straightforward way to extract the distance of a path calculated via get.shortest.paths()
? 有没有一种直接的方法来提取通过
get.shortest.paths()
计算的路径的距离?
Here is some reproducible code that exemplifies my problem: 以下是一些可重现的代码,可以解释我的问题:
## reproducible code:
df2 = rbind(c(234,235,21.6),
c(234,326,11.0),
c(235,241,14.5),
c(326,241,8.2),
c(241,245,15.3),
c(234,245,38.46))
df2 = as.data.frame(df2)
names(df2) = c("start_id","end_id","newcost")
require(igraph)
g2 <- graph.data.frame(df2, directed=FALSE)
class(g2)
print(g2, e=TRUE, v=TRUE)
## calculate shortest path between vertex 234 and 245
(tmp2 = get.shortest.paths(g2, from='234', to='245',weights=E(g2)$newcost))
## print route vertices:
V(g2)[tmp2[[1]]]
## print distance of each route segment:
## ??
## calculate distance using 'newcost' weights:
## ?? sum( route segments ) ??
You can use shortest.paths
function, eg: 您可以使用
shortest.paths
函数,例如:
# compute the min distances from '234' to all other vertices
tmp3 <- shortest.paths(g2,v='234',weights=E(g2)$newcost)
# print min distance from '234' to '245'
tmp3[1, which(V(g2)$name == '245')]
The distance computed by the algorithm is 34.5 = 11 + 8.2 + 15.3
, as shown in the following picture: 算法计算的距离为
34.5 = 11 + 8.2 + 15.3
,如下图所示:
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