如何删除字符串中HTML标记中的所有HTML属性

Question

I am trying to take a string that has HTML, strip out some tags (img, object) and all other HTML tags, strip out their attributes. For example:

<div id="someId" style="color: #000000">
   <p class="someClass">Some Text</p>
   <img src="images/someimage.jpg" alt="" />
   <a href="somelink.html">Some Link Text</a>
</div>

Would become:

<div>
   <p>Some Text</p>
   Some Link Text
</div>

I am trying:

string.replaceAll("<\/?[img|object](\s\w+(\=\".*\")?)*\>", ""); //REMOVE img/object

I am not sure how to strip all attributes inside a tag though.

Any help would be appreciated.

Thanks.

Answer 1

I would not recommend regex for this if you want to filter specific tags. This is going to be hell of a job and never going to be fully reliable. Use a normal HTML parser like Jsoup . It offers the Whitelist API to clean up HTML. See also this cookbook document .

Here's a kickoff example with help of Jsoup which only allows <div> and <p> tags next to the standard set of tags of the chosen Whitelist which is Whitelist#simpleText() in the below example.

String html = "<div id='someId' style='color: #000000'><p class='someClass'>Some Text</p><img src='images/someimage.jpg' alt='' /><a href='somelink.html'>Some Link Text</a></div>";
Whitelist whitelist = Whitelist.simpleText(); // Whitelist.simpleText() allows b, em, i, strong, u. Use Whitelist.none() instead if you want to start clean.
whitelist.addTags("div", "p");
String clean = Jsoup.clean(html, whitelist);
System.out.println(clean);

This results in

<div>
   <p>Some Text</p>Some Link Text
</div>

See also:

• How to implement a possibility for user to post some html-formatted data in a safe way?

Answer 2

You can remove all attributes like this:

string.replaceAll("(<\\w+)[^>]*(>)", "$1$2");

This expression matches an opening tag, but captures only its header <div and the closing > as groups 1 and 2. replaceAll uses references to these groups to join them back in the output as $1$2 . This cuts out the attributes in the middle of the tag.

Answer 3

/<(/?\\w+) .*?>/<\\1>/可能有效 - 获取标记（匹配组）并读取任何属性，直到关闭括号，并将其替换为仅支持和标记。

Answer 4

如果您使用SAX或DOM，并且获取节点名称和值，并删除所有属性，可能会容易得多。