[英]SQL Statement Not Returning Anything
I have a form whereby users are required to anwser their own security question before proceeding further. 我有一张表格,要求用户在继续之前先回答自己的安全问题。 my form is as follows:
我的表格如下:
<form action="securitychecked.php" method="post">
<table width="70%" border="0">
<tr>
<td><?php $result = mysql_query("SELECT secret_question FROM public WHERE active = 'activated' AND ni = '". $_SESSION['ni']."'")
or die(mysql_error());
if (mysql_num_rows($result) == 0) {
echo '<hr><h4>This Person Has Not Setup A Security Question</h4><hr> ';
} else {
while($info = mysql_fetch_array($result))
{
echo $info['secret_question'];
}
}?></td>
<td><span id="sprytextfield1">
<input type="text" name="secret_answer" id="secret_answer" />
<span class="textfieldRequiredMsg">*</span></span></td>
</tr>
<tr>
<td> </td>
<td><br /><input name="" type="submit" value="Continue" /></td>
</tr>
</table>
</form>
my php code looks like this: 我的PHP代码看起来像这样:
<?php
$secret_anwser=$_POST['secret_anwser'];
$secret_anwser = stripslashes($secret_anwser);
$secret_anwser = mysql_real_escape_string($secret_anwser);
$sql="SELECT secret_anwser FROM public WHERE secret_anwser ='$secret_anwser' AND active = 'activated' AND ni = '". $_SESSION['ni']."'";
$result=mysql_query($sql);
// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
if($count==1){
header("location:votenow.php");
}
?>
I have a table called public and a field called 'secret_anwser' but i keep on getting a blank page even with the right value being entered. 我有一个名为public的表,一个名为“ secret_anwser”的字段,但是即使输入正确的值,我仍会保持空白页。 can anyone help me?
谁能帮我?
thanks 谢谢
I guess all the secret_anwser
in your PHP are typo's. 我猜您的PHP中所有
secret_anwser
都是错字。
At least the fields name is secret_answer but you try to get $_POST['secret_anwser'];
至少字段名称是secret_answer,但是您尝试获取
$_POST['secret_anwser'];
, you'll never find anything inside the DB. ,您将永远不会在数据库中找到任何东西。
The names of the DB and the table also may be wrong. 数据库和表的名称也可能是错误的。
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