[英]Running multiple C programs from a C program under Linux
I'm trying to learn a bit or 2 about process communication under Linux, so I wrote 2 simple C programs that communicate with each other. 我正在尝试在Linux下学习一些关于进程通信的内容,所以我编写了两个相互通信的简单C程序。
However, it's a bit annoying to have to run them manually every single time, so I'd like to know is there a way to make a program that will run them both, something like this: 但是,每次都必须手动运行它们有点烦人,所以我想知道是否有办法制作一个可以同时运行它们的程序,如下所示:
./runner program1 program2
I'm using latest Ubuntu and Bash shell. 我正在使用最新的Ubuntu和Bash shell。
run.sh script run.sh脚本
#!/bin/sh
./program1 &
./program2 &
run command: 运行命令:
$sh run.sh
This line will do (in Bash): 这行会做(在Bash中):
program1 & program2 &
If you want to record the output: 如果要记录输出:
program1 >output1.txt & program2 >output.txt &
If you want to run the commands in two separate terminals: 如果要在两个单独的终端中运行命令:
xterm -e program1 & xterm -e program2 &
Why not use this: 为什么不用这个:
./program1;./program2
or 要么
./program1 &;./program2 &
I don't know why somebody thinks it's not useful,but it really works. 我不知道为什么有人认为它没用,但确实有效。
Surely you can write a script,but what's the content of the script?Still the same thing. 当然你可以写一个脚本,但脚本的内容是什么?还是一样的。
And you can change it at once with no need to open the script first. 您可以立即更改它,而无需先打开脚本。
只需编写一个shell脚本来执行您想要的操作 - 您不需要使用C程序来运行C程序。
Do do exactly what you asked, first created a file called runner
which will be the shell script. 完全按照你的要求做,首先创建一个名为runner
的文件,它将是shell脚本。
#!/bin/bash
for arg in $@
do
$arg &
done
$@
in bash is an array of all the arguments passed to the script, this makes the script no restricted to only launching 2 programs. bash中的$@
是传递给脚本的所有参数的数组,这使得脚本不限于仅启动2个程序。 Note any programs your launch with this scripts need to be on the $PATH
or passed to the script as ./program1
. 请注意,使用此脚本启动的任何程序都必须位于 $PATH
或者以./program1
传递给脚本。
./runner ./program1 program2
In the example program1
is not on the $PATH
but program2
is. 在示例中, program1
不在$PATH
但是program2
是。
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