binary'=='：找不到带有'std :: string'类型的左手操作数的运算符（或者没有可接受的转换）

Question

I am writing a template class function comparing std::strings. std::string is the template parameter. My problem is that I can't compare two const string with "==" operator, then I think I create two non-const temporary string variables to performe the comparation, but it still can't compile. Don't know why.

class VGraph is instanced as VGraph<std::string, std::string> myGraph;

template <typename V, typename E>
size_t VGraph<V, E>::find(const V& vert)
{
    V temp = vert; // (1)
    for (size_t i=0; i<graph.size(); i++)
    {
        V noneConst = graph[i].getVertex(); // (2)
        if (temp==noneConst)// I think broblem is here, and tried to fix using (1)(2)
            return i;
    }
    return graph.size();
}

Prototype of related function

template <typename V, typename E>
const V& VVertex<V, E>::getVertex();

Answer 1

You probably forgot an explicit:

#include <string>

The std::string class is defined by a another header you included, but not the operator == .