[英]How to differentiate the dict key and values based on delimiters
I have a dict of type x={'a':'1','b':'2','c;0':'a1;b1;b2;b3;b4','c;1':'a2;b2;b3;b4;b5;b6'}
我有一个类型为
x={'a':'1','b':'2','c;0':'a1;b1;b2;b3;b4','c;1':'a2;b2;b3;b4;b5;b6'}
的字典x={'a':'1','b':'2','c;0':'a1;b1;b2;b3;b4','c;1':'a2;b2;b3;b4;b5;b6'}
i am writing program like this 我正在写这样的程序
for key,values in x.iteritems():
if key.split(";") is True:
print key,value
else:
print key,value
its not working properly. 它无法正常工作。
in output what i want on execution of 在输出中我想要执行什么
if key.split(";") is False
print key,values
output should be 输出应该是
a 1
b 2
in output what i want on execution of 在输出中我想要执行什么
if key.split(";") is True
print key,values
output should be 输出应该是
c;0 a1;b1;b2;b3;b4,
c;1 a2;b2;b3;b4;b5;b6
I think you don't really need any if
/ else
condition since you're printing key/value pairs for both cases: 我认为您真的不需要任何
if
/ else
条件,因为在两种情况下您都将打印键/值对:
>>> for k, v in x.iteritems():
... print k, v
a 1
b 2
c;1 a2;b2;b3;b4;b5;b6
c;0 a1;b1;b2;b3;b4
Looking at the output you provided, the only difference I see is that your example is ordered. 查看您提供的输出,我看到的唯一区别是示例是有序的。 If that's what you're looking for then, you can use
sorted
like this: 如果这正是您要寻找的,则可以使用如下所示的
sorted
:
>>> for k, v in sorted(x.iteritems()):
... print k, v
a 1
b 2
c;0 a1;b1;b2;b3;b4
c;1 a2;b2;b3;b4;b5;b6
I hope this helps. 我希望这有帮助。
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