[英]Convert from double to decimal
I am developing a weather application in C# using the Google weather XML file and I am having trouble using calculations in a class file. 我正在使用Google天气XML文件在C#中开发天气应用程序,我在类文件中使用计算时遇到问题。 I am trying to convert farenheit to celcius with the folliowing method: 我试图用下面的方法将farenheit转换为celcius:
public static class Helper
{
public static decimal CalculateTemp(decimal input)
{
return Math.Round((input - 32) * 5 / 9 / 1.0) * 1.0 + "°C";
}
}
"input" is where the weather data is called such as the highest temp. “输入”是调用天气数据的地方,例如最高温度。 of today. 今天的。 I am getting the following errors upon compiling: 我在编译时遇到以下错误:
Error 23: The best overloaded method match for 'Weather.Helper.CalculateTemp(decimal)' has some invalid arguments 错误23:'Weather.Helper.CalculateTemp(decimal)'的最佳重载方法匹配有一些无效的参数
Error 24: Argument 1: cannot convert from 'double' to 'decimal' 错误24:参数1:无法从'double'转换为'decimal'
Error 25 : Operator '/' cannot be applied to operands of type 'decimal' and 'double' 错误25:运算符'/'不能应用于'decimal'和'double'类型的操作数
I am not sure how to fix this.. 我不知道如何解决这个问题..
Don't use decimal
for a temperature, double
is enough. 不要使用decimal
表示温度, double
就足够了。
Also, don't return "°C"
cause it's a number, not a string: 另外,不要返回"°C"
因为它是一个数字,而不是一个字符串:
public static double CalculateTemp(double input)
{
return Math.Round((input - 32) * 5 / 9);
}
1.0
is a double
, not a decimal
. 1.0
是double
decimal
,而不是decimal
。 Use the suffix m
or M
to mark a number as a decimal
. 使用后缀m
或M
将数字标记为decimal
。
("M" stands for "Money", as this type is normally used for financial transactions.) (“M”代表“Money”,因为此类型通常用于金融交易。)
(input - 32) * 5M / 9M
and you won't even need the * 1.0
你甚至不需要* 1.0
if you want to use the decimal (rather than double), you'd have to refactor as: 如果你想使用小数(而不是双倍),你必须重构为:
public static class Helper
{
public static string CalculateTemp(decimal input)
{
return Math.Round(((input - 32) * 5 / 9 / 1.0m)) + "°C";
}
}
or: 要么:
public static class Helper
{
public static string CalculateTemp(decimal input)
{
return Math.Round(((input - 32) * 5 / 9 / (decimal)1.0)) + "°C";
}
}
notice also that you have to change the method signature to return a string due to the "°C"
at the end. 另请注意,由于末尾的"°C"
,您必须更改方法签名以返回字符串。
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