[英]python regex split first character
eg I have Name : John Frank Smith 我有名字: 约翰弗兰克史密斯
What I want is to seperate by first space 我想要的是通过第一空间分开
so array will be [0]=John [1]=Frank Smith 所以数组将是[0] =约翰[1] =弗兰克史密斯
what I tried, I replace space by ~ and tried to split by regex. 我尝试了什么,我用〜替换空间,并试图通过正则表达式进行拆分。
import re
s="John~Frank~Smith"
l=re.compile(r'/~(.+)?/').split(s)
output is: 输出是:
['John~Frank~Smith']
How can I achieve as described above? 如何实现上述目标?
first I don't know how to put space in regex. 首先我不知道如何在正则表达式中放置空格。
Use str.split()
with the maxsplit
parameter: 将
str.split()
与maxsplit
参数一起使用:
>>> s = "John Frank Smith"
>>> s.split(None, 1)
['John', 'Frank Smith']
Note: This will split on multiple occurrences of whitespace, so a string like 注意:这会在多次出现的空白时分割,所以字符串就像
John Frank Smith
would give the same result. 会给出相同的结果。 If you only want a single space as a separator, use
s.split(' ', 1)
. 如果您只想要一个空格作为分隔符,请使用
s.split(' ', 1)
。
If you want to use a regex: 如果你想使用正则表达式:
>>> re.split(r'~', "John~Frank~Smith",1)
['John', 'Frank~Smith']
The ~
are from your example. ~
来自你的榜样。
no need for regex, use split() : 不需要正则表达式,使用split():
s="John~Frank~Smith"
s.split('~',1)
['John', 'Frank~Smith']
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