Java中的String.format（）和十六进制数字

Question

I'm trying to figure out why String.format() is behaving the way it does.

Context: Systems programming class, writing an assembler.

There is a 5 character hex field in the object file, which I am creating from a value.

Tried using: String.format("%05X", decInt);

This works as intended for positive numbers (11 -> 0000B ) However it fails for negative numbers (-1 -> FFFFFFFF instead of FFFFF )

I suppose I could just take a substring of the last 5 characters, but I would still like to figure out why it behaves this way.

Answer 1

The width used in format is always a minimum width. In this case, instead of using sub string operations I would suggest:

  String.format("%05X", decInt & 0xFFFFF);

Answer 2

Format width only works to create a minimum number of digits, and only has effect on leading zeroes.

Instead of substring, you could use a bit mask:

String.format("%05X", decInt & 0x0FFFFF)

By the way, 11 -> 0000B , not 0000A as claimed in your question.