如何使用xslt从XML提取元素的属性并以不同的样式显示

Question

I am new to XSLT. I am working transforming an XML file from one format to another format. I also want to extract values from an element and display the them in bold format.

Sample source XML:

 <Content xmlns="uuid:4522eb85">
      <first xmlns="uuid:4522eb85">Hello World. This is first field</first>
      <second author="XYZ">Hi iam second field</second>
 </Content>

Output format required:

  <root>
     <aaa>Hello World. This is first field</aaa>
     <bbb><author>**XYZ**</author>Hi iam second field</bbb>
  <root>

I am unable to extract attributes from a tag and display with style(say bold).

Please help. Thank you in advance.

Answer 1

This XSLT outputs exactly what you ask for.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:c="uuid:4522eb85" exclude-result-prefixes="c">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>

    <xsl:template match="/c:Content">
        <root>
            <aaa><xsl:value-of select="c:first"/></aaa>
            <bbb><author>**<xsl:value-of select="c:second/@author" />**</author><xsl:value-of select="c:second" /></bbb>
        </root>
    </xsl:template>
</xsl:stylesheet>

But as Jeremy suggests, you may want to consider first taking an (online) XSLT training if you want to get much further.

Answer 2

If you want to display the text with style then you have to display the content in html. You should use XSLT to get the info from XML and create a HTML output with you required style