[英]PHP json_encode won't output proper result
I want to output users via a json object but when I try to output their songs list it only outputs the last one. 我想通过json对象输出用户,但是当我尝试输出他们的歌曲列表时,它只输出最后一个。 I want to get this list into an array.
我想把这个列表放到一个数组中。
this is my array push while looping through users, 这是我在循环浏览用户时的数组推送,
array_push($arrayUsers, array(
'username' => $user['username'],
'id' => $user['_id'],
'favSongs' => array(
'title' =>'song1',
'title' =>'song2'
)
)
);
but this is what I get back (missing song title), 但这是我回来的(缺少歌曲标题),
[{"username":"asdfasdfasd","id":{"$id":"4f58d7227edae19c02000000"},"songs":{"title":"song2"}}]
I want it to output the songs like this, but am confused how to get it to do this using PHP: 我希望它输出这样的歌曲,但我很困惑如何使用PHP来做到这一点:
"songs":[{"title": "song1"}, {"title": "song2"}]
'favSongs' => array(
'title' => 'song1',
'title' => 'song2'
)
PHP will replace the 'title' key with the last one declared. PHP将用声明的最后一个键替换'title'键。
"songs":[{"title": "song1"}, {"title": "song2"}]
This is an array of objects, so in PHP it needs to be an array of arrays. 这是一个对象数组,因此在PHP中它需要是一个数组数组。
'favSongs' => array(
array('title' => 'song1'),
array('title' => 'song2')
)
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