Java-如何将一个数组拆分为四个单独的数组？

Question

I have an array which contains a string of numbers such as: 1011

and I wanted to split it up into four separate arrays containing each of those values. How do I do this?

String [] array = {1,0,1,1}; 

//would I do something like this:

array.substring(0,4)

Answer 1

您应该可以使用Arrays.copyOfRange（...）来执行此操作。

Answer 2

Option 1 would be to simply create a new array for each item in the array you have... could be done generically like this:

public <T> List<T[]> splitEachItemIntoOwnArray(T[] original) {
  List<T[]> result = new ArrayList<T[]>();
  if (original == null) return result;

  for (T t : original) {
    result.add((T[])new Object[] {t});
  }

  return result;
}

Option 2, you could also achieve this generically with the Arrays.copyOfRange() method:

public <T> List<T[]> splitEachItemIntoOwnArray2(T[] original) {
    List<T[]> result = new ArrayList<T[]>();
    if (original == null) return result;

    for (int i = 0; i < original.length; i++) {
        result.add(Arrays.copyOfRange(original,i,i+1));
    }

    return result;
}

Options 1 and 2 work if you always want the each item of the original array split into its own array. If you might want every N items of the original array split into their own, this should work:

public <T> List<T[]> splitEachItemIntoOwnArray2(T[] original, int size) {
    List<T[]> result = new ArrayList<T[]>();
    if (original == null) return result;

    int curPos = 0;
    while (curPos < original.length) {
        int remaining = original.length - curPos+1;
        if (remaining <= size) {
            result.add(Arrays.copyOfRange(original,curPos,original.length));
        } else {
            result.add(Arrays.copyOfRange(original,curPos,curPos+size));
        }
        curPos += size;
    }

    return result;
}

Answer 3

There's no splitting afaik, but you can copy it into new arrays using a range

check out copyOfRange

static <T,U> T[] copyOfRange(U[] original, int from, int to, Class<? extends T[]> newType)

usage follows:

String [] array = {1,0,1,1}; 
// Copies from element 0 to 0
String[] array1 = Arrays.copyOfRange(array, 0, 0);

Answer 4

public static void main(String[] args) {
  int[] array = {1,0,1,1}; 
    int[] array1 = Arrays.copyOfRange(array, 0, 1);
    int[] array2 = Arrays.copyOfRange(array, 1, 2);
    int[] array3 = Arrays.copyOfRange(array, 2, 3);
    int[] array4 = Arrays.copyOfRange(array, 3, 4);
    System.out.println(array1[0]);
    System.out.println(array2[0]);
    System.out.println(array3[0]);
    System.out.println(array4[0]);
}