Django模板将模板变量传递到剪切过滤器

Question

I am trying to pass a template into a cut filter, something like this

{{ myVariable|cut:"something + templateVariable" }}

I've tried:

{{ myVariable|cut:"something"|add:templateVariable }}

and

{{ myVariable|cut:"something {{ templateVariable }}" }}

but these does not work.

Is this possible to do?

Answer 1

It should work with a temporary variable using the with tag :

{% with myFilter="something"|add:templateVariable %}
    {{ myVariable|cut:myFilter }}
{% endwith %}

Or in Django 1.2 and older:

{% with "something"|add:templateVariable as myFilter %}
    {{ myVariable|cut:myFilter }}
{% endwith %}

Add does not support concatenation of string and int but you could easily make a template filter that converts to string for example:

from django import template

register = template.Library()

@register.filter
def to_unicode(mixed):
    return unicode(mixed)

Would allow a such template tag expression some_int|to_unicode|add:'foo' .