如何在结构中存储函数指针？

Question

I have declared typedef void (*DoRunTimeChecks)();

How do I store that as a field in a struct? How do I assign it? How do I call the fn()?

Answer 1

Just put it in like you would any other field:

struct example {
   int x;
   DoRunTimeChecks y;
};

void Function(void)
{
}

struct example anExample = { 12, Function };

To assign to the field:

anExample.y = Function;

To call the function:

anExample.y();

Answer 2

#include <stdio.h>

typedef void (*DoRunTimeChecks)();

struct func_struct {
    DoRunTimeChecks func;
};

void function()
{
    puts("hello");
}

int main()
{
    struct func_struct func_struct;
    func_struct.func = function;
    func_struct.func();
    return 0;
}