用于检查字符串中字符的正则表达式

Question

I have a text to validate using regex,

Text field is allowed to have all the characters az and 0-9 except for alphabets (i,o,q).

I tried something like this but cannot get it to work '/[^(oOiIqQ)]/'

Answer 1

A simple way for exclusions like this is to use negative lookahead. State what you want:

/^(?:[a-z0-9])+\z/i

Then exclude the items you don't want:

/^(?:(?![ioq])[a-z0-9])+\z/i

Answer 2

You cannot use parenthesis in [ ... ].

You have to use something like '/[0-9a-hj-npr-zA-HJ-NPR-Z]/'

If you want to be sure your text only has those characters, use:

'/^[0-9a-hj-npr-zA-HJ-NPR-Z]+$/'

So you can match a string containing any number of those characters, and only those.

Answer 3

This might works: [a-hj-npr-z] Maybe you can add the flag i at the end of your regexp for case insensibility.

(yours will allow EVERY characters except those you specified)

if (preg_match('#^[0-9a-hj-npr-z]+$#i', $string)) {
   //string OK
}

Answer 4

也许是这样的/^[0-9a-hj-npr-z A-HJ-NPR-X]+$/

Answer 5

我假设对您的做了一些改动，然后尝试：

^[^oOiIqQ]+$

Answer 6

为此，有一个非常简单的解决方案，其中考虑了负正则表达式（这使正则表达式更短且更具可读性）

[^ioqIOQ]+