[英]Assigning ID to a widget using GQuery
I need to wrap a widget with an ID, so I used GQuery to do that, like so: 我需要用ID包装一个小部件,因此我使用GQuery来做到这一点,就像这样:
GQuery g = $(signupButton);
g.id("signupButton");
Now I need to get the instance of the actual Button or Widget using the GQuery object, is that possible? 现在,我需要使用GQuery对象获取实际的Button或Widget的实例,这可能吗?
Will the g.get(0)
return the wrapped instance of that Button/Widget? g.get(0)
返回该Button / Widget的包装实例?
use the widget() method 使用widget()方法
Button b = g.widget();
//later if you want to query your button via its id
Button b = $("#signupButton").widget()
Julien 朱利安
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