C＃：Array.Sort方法的两倍？

Question

I have an array ( double ) : ox_test with a known number of elements.

when I code :

Array.Sort(ox_test);

and then, just to see if the array it's sorted :

for (int y = 1; y <= ox_test.Length; y++)
     MessageBox.Show(".x: " + ox_test[y]);

.. I get ... 0, 0, 0, 0, 0 ( if the number of elements was 5 ). Please help, thank you!

So i modified the both for loops:

for (int y = 0; y < ox_test.Length; y++)
    MessageBox.Show(".x: " + ox_test[y]);
    // HERE  i get the values not sorted but != 0

Array.Sort(ox_test);

for (int y = 0; y < ox_test.Length; y++)
    MessageBox.Show(".x s: " + ox_test[y]);
    // HERE i get only 0 values

Answer 1

// sort double array
double[] doubleArray = new double[5] { 8.1, 10.2, 2.5, 6.7, 3.3 };
Array.Sort(doubleArray);
// write array
foreach (double d in doubleArray) Console.Write(d + " ");  // output: 2.5 3.3 6.7 8.1 10.2

Answer 2

You should start from 0 instead of 1.

for (int y = 0; y < ox_test.Length; y++)
    MessageBox.Show(".x: " + ox_test[y]);

Also, please be sure of initialization of ox_test array.

Answer 3

Try with this code:

Array.Sort(ox_test);

foreach (double i in ox_test)
{
    Console.Write(i + " ");
}