[英]Perl: Read path from command line
I'm newbie in perl and I got some problem with one thing. 我是Perl的新手,一件事有点问题。
I have code: 我有代码:
$original_file = "y:\\Users\\XXX\\perlScript\\test1.xml";
$new_file = "y:\\Users\\XXX\\perlScript\\summary_test1.xml";
copy($original_file, $new_file) or die "File cannot be copied";
I need read path from cmd command line (I use batch file). 我需要从cmd命令行读取路径(我使用批处理文件)。 For Example:
例如:
>summary.bat c>\path\file_name.xml
After copy I'd like create summary_file_name.xml
to same folder 复制后,我想将
summary_file_name.xml
创建到同一文件夹
Thanks 谢谢
Are you asking how a Perl program gets its command line arguments? 您是在问Perl程序如何获取其命令行参数吗? You'll find them in the
@ARGV
array. 您将在
@ARGV
数组中找到它们。
You want to use File::Basename
. 您想使用
File::Basename
。 This is a standard library in Perl, at least as early as 5.14, so you do not need to install anything new. 这是Perl中的标准库,至少早在5.14之前,因此您不需要安装任何新东西。
use File::Basename;
my($filename, $directories, $suffix) = fileparse($original_file);
my $new_file = $directories . "/summary.xml";
For more information, see the Perl Docs . 有关更多信息,请参见Perl Docs 。
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